The number of students absent in a class were recorded every day for 120 days and the information is given in the following frequency table:
No. of students absent ($x$): | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
No. of days ($f$): | 1 | 4 | 10 | 50 | 34 | 15 | 4 | 2 |
Find the mean number of students absents per day.
Given:
The number of students absent in a class were recorded every day for 120 days and the information is given in the frequency table
To do:
We have to find the mean number of students absents per day.
Solution:
Let the assumed mean be $A=3$
Number of students absent ($x_i$) | Number of days ($f_i$) | $d_i = x_i -A$ $A = 3$
| $f_i \times\ d_i$ |
0 | 1 | $-3$ | $-3$ |
1 | 4 | $-2$ | $-8$ |
2 | 10 | $-1$ | $-10$ |
3- $A$ | 50 | 0 | 0 |
4 | 34 | 1 | 34 |
5 | 15 | 2 | 30 |
6 | 4 | 3 | 12 |
7 | 2 | 4 | 8 |
Total | $\sum{f_i}=120$ | | $\sum{f_id_i}=63$
|
We know that,
Mean $=A+\frac{\sum{f_id_i}}{\sum{f_i}}$
Therefore,
Mean $=3+\frac{63}{120}$
$=3+0.525$
$=3.525$
The mean number of students per day is $3.53$.
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