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How to create a new image from a JPEG file using the imagecreatefromjpeg() function in PHP?
imagecreatefromjpeg() is an inbuilt function in PHP that is used to create a new image from a JPEG file. It returns an image identifier representing the image obtained from the given filename.
Syntax
resource imagecreatefromjpeg(string $filename)
Parameters
imagecreatefromjpeg() uses only one parameter, $filename, that holds the name of the image or path to the JPEG image.
Return Values
imagecreatefromjpeg() returns an image resource identifier on success, and it gives an error on false.
Example 1
<?php // Load an image from local drive/file $img = imagecreatefromjpeg('C:\xampp\htdocs\test\1.jpeg'); // it will show the loaded image in the browser header('Content-type: image/jpg'); imagejpeg($img); imagedestroy($img); ?>
Output
Example 2
<?php // Load a JPEG image from local drive/file $img = imagecreatefromjpeg('C:\xampp\htdocs\test\1(a).jpeg'); // Flip the image imageflip($img, 1); // Save the GIF image in the given path. imagejpeg($img,'C:\xampp\htdocs\test\1(b).png'); imagedestroy($img); ?>
Input Image
Output Image
Explanation − In Example 2, we loaded the jpeg image from the local path using the imagecreatefromjpeg() function. Thereafter, we used the imageflip() function to flip the image.
Example 3 − Handling errors during loading of a JPEG image
<?php function LoadJpeg($imgname) { /* Attempt to open */ $im = @imagecreatefromjpeg($imgname); /* See if it failed */ if(!$im) { /* Create a black image */ $im = imagecreatetruecolor(700, 300); $bgc = imagecolorallocate($im, 0, 0, 255); $tc = imagecolorallocate($im, 255,255, 255); imagefilledrectangle($im, 0, 0, 700, 300, $bgc); /* Output an error message */ imagestring($im, 20, 80, 80, 'Error loading ' . $imgname, $tc); } return $im; } header('Content-Type: image/jpeg'); $img = LoadJpeg('bogus.image'); imagejpeg($img); imagedestroy($img); ?>
Output
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