# How to create a new image from a JPEG file using the imagecreatefromjpeg() function in PHP?

PHPServer Side ProgrammingProgramming

imagecreatefromjpeg() is an inbuilt function in PHP that is used to create a new image from a JPEG file. It returns an image identifier representing the image obtained from the given filename.

## Syntax

### Return Values

imagecreatefromjpeg() returns an image resource identifier on success, and it gives an error on false.

## Example 1

<?php
// Load an image from local drive/file
$img = imagecreatefromjpeg('C:\xampp\htdocs\test\1.jpeg'); // it will show the loaded image in the browser header('Content-type: image/jpg'); imagejpeg($img);

imagedestroy($img); ?> ## Output ## Example 2 <?php // Load a JPEG image from local drive/file$img = imagecreatefromjpeg('C:\xampp\htdocs\test\1(a).jpeg');

// Flip the image
imageflip($img, 1); // Save the GIF image in the given path. imagejpeg($img,'C:\xampp\htdocs\test\1(b).png');
imagedestroy($img); ?> ## Input Image ## Output Image Explanation − In Example 2, we loaded the jpeg image from the local path using the imagecreatefromjpeg() function. Thereafter, we used the imageflip() function to flip the image. ## Example 3 − Handling errors during loading of a JPEG image <?php function LoadJpeg($imgname) {
/* Attempt to open */
$im = @imagecreatefromjpeg($imgname);

/* See if it failed */
if(!$im) { /* Create a black image */$im = imagecreatetruecolor(700, 300);
$bgc = imagecolorallocate($im, 0, 0, 255);
$tc = imagecolorallocate($im, 255,255, 255);
imagefilledrectangle($im, 0, 0, 700, 300,$bgc);

/* Output an error message */
imagestring($im, 20, 80, 80, 'Error loading ' .$imgname, $tc); } return$im;
}
$img = LoadJpeg('bogus.image'); imagejpeg($img);
?>