How can I make the xtick labels of a plot be simple drawings using Matplotlib?

To make xtick labels of a plot be simple drawings using Matplotlib, we can take the following steps −

Set the figure size and adjust the padding between and around the subplots.
Initialize the y position of simple drawings.
Create a new figure or activate an existing figure using figure() method.
Add an '~.axes.Axes' to the figure as part of a subplot arrangement using add_subplot()method.
Plot a line using plot() method.
Set the X-axis ticks using set_ticks() method.
Set empty tick labels.
Add circles and rectangles patches using add_patch() method. Instantiate Circle() and Rectangle() class.
To display the figure, use show() method.

Example

import matplotlib.pyplot as plt
import matplotlib.patches as patches

plt.rcParams["figure.figsize"] = [7.50, 3.50]
plt.rcParams["figure.autolayout"] = True

y = -.75
fig = plt.figure()

ax = fig.add_subplot(111)
ax.plot(range(10))

ax.get_xaxis().set_ticks([2, 4, 6, 8])
ax.get_xaxis().set_ticklabels([])

ax.add_patch(patches.Circle((2, y), radius=.2,
                           clip_on=False, facecolor='red'))
ax.add_patch(patches.Circle((4, y), radius=.2,
                           clip_on=False, facecolor='yellow'))
ax.add_patch(patches.Rectangle((6 - .1, y - .05), .2, .2,
                              clip_on=False, facecolor='blue'))
ax.add_patch(patches.Rectangle((8 - .1, y - .05), .2, .2,
                              clip_on=False, facecolor='green'))

plt.show()

Output

Rishikesh Kumar Rishi

Published on 09-Jun-2021 11:38:40

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