Get square root of a number using Math.sqrt in Java

Java 8 Object Oriented Programming Programming

In order to get the square root of a number in Java, we use the java.lang.Math.pow() method. The Math.pow(double a) method accepts one argument of the double data type and returns a value which is the square root of the argument.

Declaration − The java.lang.Math.sqrt() method is declared as follows −

public static double sqrt(double a)

where a is the number whose square root is to be found.

Let us see a program where we find the square root of number using the Math.sqrt() method.

Example

Live Demo

import java.lang.Math;
public class Example {
   public static void main(String[] args) {
      // declaring and initializing some double values
      double x = 25;
      double y = 81;
      // computing the square roots
      System.out.println("The square root of "+ x + " is "+ Math.sqrt(x));
      System.out.println("The square root of "+ y + " is "+ Math.sqrt(y));
   }
}

Output

The square root of 25.0 is 5.0
The square root of 81.0 is 9.0

Ankith Reddy

Published on 07-Jan-2019 11:38:26

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