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Finding n-th term of series 3, 13, 42, 108, 235... in C++
In this problem, we are given a number n. Our task is to find the n-th term of series 3, 13, 42, 108, 235...
Let's take an example to understand the problem,
Input : 5 Output : 235
Solution Approach
The series can be represented as the sum of cubes of first n natural numbers. The formula for that is (n*(n+1)/2)2. Also if we add 2* to it we will get the required series.
The formula for sum of the series is (n*(n+1)/2)2+2*n.
For n = 5 sum by the formula is
(5 * (5 + 1 ) / 2)) ^ 2 + 2*5
= (5 * 6 / 2) ^ 2 + 10
= (15) ^ 2 + 10
= 225 + 10
= 235
Example
Program to illustrate the working of our solution
#include <iostream>
using namespace std;
int findNthTerm(int N)
{
return ((N * (N + 1) / 2)*(N * (N + 1) / 2) ) + 2 * N;
}
int main()
{
int N = 5;
cout<<"The Nth term fo the series n is "<<findNthTerm(N);
return 0;
}Output
The Nth term fo the series n is 235
Updated on: 01-Feb-2022
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