- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Find the roots of the following quadratic equations by factorisation:
(i) $x^2 -3x – 10 = 0$
(ii) $2x^2 + x – 6 = 0$
(iii) $\sqrt{2}x^2 + 7x + 5\sqrt{2} = 0$
(iv) $2x^2 – x + \frac{1}{8} = 0$
(v) $100x^2 – 20x+ 1 = 0$
To do:
We have to find the roots of the given quadratic equations by factorisation.
Solution:
(i) $x^2-3x-10=0$
$x^2-5x+2x-10=0$
$x(x-5)+2(x-5)=0$
$(x-5)(x+2)=0$
$x-5=0$ or $x+2=0$
$x=5$ or $x=-2$
Hence, the roots of the given quadratic equation are $-2$ and $5$.
(ii) $2x^2+x-6=0$
$2x^2+4x-3x-6=0$
$2x(x+2)-3(x+2)=0$
$(x+2)(2x-3)=0$
$x+2=0$ or $2x-3=0$
$x=-2$ or $2x=3$
$x=-2$ or $x=\frac{3}{2}$
Hence, the roots of the given quadratic equation are $-2$ and $\frac{3}{2}$.
(iii) $\sqrt{2}x^2+7x+5\sqrt2=0$
To factorise $\sqrt{2}x^2+7x+5\sqrt2=0$, we have to find two numbers $m$ and $n$ such that $m+n=7$ and $mn=\sqrt{2}\times(5\sqrt{2})=5(\sqrt2)^2=10$.
If $m=5$ and $n=2$, $m+n=5+2=7$ and $mn=(5)2=10$.
$\sqrt{2}x^2+5x+2x+5\sqrt2=0$
$\sqrt{2}x(x+\sqrt2)+5(x+\sqrt2)=0$
$(\sqrt{2}x+5)(x+\sqrt2)=0$
$\sqrt{2}x+5=0$ or $x+\sqrt2=0$
$\sqrt{2}x=-5$ or $x=-\sqrt2$
$x=-\frac{5}{\sqrt2}$ or $x=-\sqrt2$
The values of $x$ are $-\frac{5}{\sqrt2}$ and $-\sqrt2$.
(iv) $2x^2 – x + \frac{1}{8} = 0$
$\frac{8(2x^2)-8(x)+1}{8}=0$
$16x^2-8x+1=0(8)$
$16x^2-8x+1=0$
$16x^2-4x-4x+1=0$
$4x(4x-1)-1(4x-1)=0$
$(4x-1)(4x-1)=0$
$4x-1=0$ or $4x-1=0$
$4x=1$ or $4x=1$
$x=\frac{1}{4}$ or $x=\frac{1}{4}$
Hence, the roots of the given quadratic equation are $\frac{1}{4}$ and $\frac{1}{4}$.
(v) $100x^2 – 20x+ 1 = 0$
$100x^2-10x-10x+1=0$
$10x(10x-1)-1(10x-1)=0$
$(10x-1)(10x-1)=0$
$10x-1=0$ or $10x-1=0$
$10x=1$ or $10x=1$
$x=\frac{1}{10}$ or $x=\frac{1}{10}$
Hence, the roots of the given quadratic equation are $\frac{1}{10}$ and $\frac{1}{10}$.