Solve the following quadratic equation by factorization:

$x^2-(\sqrt{2}+1)x+\sqrt2=0$


Given:

Given quadratic equation is $x^2-(\sqrt{2}+1)x+\sqrt2=0$.

To do:

We have to solve the given quadratic equation.


Solution:

$x^2-(\sqrt{2}+1)x+\sqrt2=0$

$x^2-\sqrt{2}x-x+\sqrt2=0$

$x(x-\sqrt2)-1(x-\sqrt2)=0$

$(x-1)(x-\sqrt2)=0$

$x-1=0$ or $x-\sqrt2=0$

$x=1$ or $x=\sqrt2$


The values of $x$ are $1$ and $\sqrt2$.

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Updated on: 10-Oct-2022

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