Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Find the Mirror Image of a String using Python
In the given problem statement we are required to find the mirror image of a given string with the help of Python code.
Understanding The Problem
The problem at hand is to find the mirror image of the given string. The mirror image is the changed version of the given string in which every character is replaced with the mirror image of that character. Or we can say it is the reflection of the string. In real life we see ourselves in the mirror so our right part is visible in the left side in the mirror and similarly the right part shows in the left side.
Input-Output Scenario
Following is an input and its output example of mirror image of the given string −
Input string = TUTOR Output string: ROTUT
Logic for The Above Problem
To solve this problem, first we will reverse the given string with the help of the reversed function of python. And then we will replace each character with the corresponding mirror image of that character.
Algorithm
Step 1 − Define the function called get_mirror_image. And pass an argument called str.
Step 2 − Define the mirror characters dictionary as mirror_chars, this will contain all the mirror characters as a dictionary.
Step 3 − Iterate over the reversed string and replace the character with its mirror image from the above dictionary.
Step 4 − Reverse the input string using the reversed function. And store the mirror string in mirror_string variable.
Step 5 − Now get the input from the user and print the original and mirror strings.
Example
def get_mirror_image(str):
mirror_chars = {
'A': 'A', 'B': 'B', 'C': 'C', 'D': 'D', 'E': 'E', 'F': 'F', 'G': 'G', 'H': 'H', 'I': 'I', 'J': 'J', 'K': 'K', 'L': 'L', 'M': 'M', 'N': 'N', 'O': 'O', 'P': 'P', 'Q': 'Q', 'R' : 'R', 'S': 'S', 'T': 'T', 'U': 'U', 'V': 'V', 'W': 'W', 'X': 'X', 'Y': 'Y', 'Z': 'Z', ' ': ' ', 'a': 'a', 'b': '', 'c':'c', 'd':'d', 'e':'e', 'f':'f', 'g':'g', 'h':'h', 'i':'i', 'j':'j', 'k':'k', 'l':'l', 'm':'m', 'n':'n', 'o':'o', 'p':'p', 'q':'q', 'r':'r', 's':'s', 't':'t', 'u':'u', 'v':'v', 'w':'w', 'x':'x', 'y':'y', 'z':'z'
}
# Reverse and replace characters with their mirror characters
mirror_string = ''.join(mirror_chars.get(char, '') for char in reversed(str))
return mirror_string
# Testing the function
original_string = input("Enter a String: ")
mirror_string = get_mirror_image(original_string)
print("Your String is: ", original_string)
print("Mirror image of your string: ", mirror_string)
Output
Enter a String: Tutorialspoint Your String is: Tutorialspoint Mirror image of your string: tniopslairotuT
Complexity
In the code we have used a dictionary to store all the mirror characters. And took user input for the string. So based on the input, let’s say its size is n, the time complexity is O(n). Because we have used a reversed function which is used to reverse the given string and it is iterating the string for O(n) time. And to check the mirror character in the defined dictionary it takes O(1), constant time. So overall complexity is O(n).
Conclusion
The code has successfully found the mirror image of the given string. As we have learned the usage of the reversed function of Python and created a dictionary to store the mirror characters.
198 Views
To Continue Learning Please Login