Find the energy in kW h consumed in $10\ hours$ by four devices of power $500\ W$ each.

Given: Four devices of power $500\ W$ each.

To do: To find the energy in kW h consumed in $10\ hours$ by four devices.

Solution:

Number of devices $=4$

Power of each device $P=500\ W$

Total power of the four devices $=4P=4\times500=2000\ W$

Time taken to consume energy $t=10\ hr=10\times60\times60=36000\ sec.$

We know , $Power=\frac{Total\ energy}{time}$

Or $2000=\frac{Total\ energy\ consumed}{36000}$

Or $Total\ energy\ consumed=2000\times36000$

Or $Total\ energy\ consumed=62\times10^6\ Joule$

Or $Total\ energy\ consumed=6.2\times10^7\ Joule$

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Updated on: 10-Oct-2022

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