If an electric iron of $1200\ W$ is used for $30$ minutes everyday, find electric energy consumed in the month of April.

Power of electronic iron $P=1200\ W$

Time $t=30\ minutes$ per day$=30\times60\ s=1800\ seconds$

So, energy consumed per day $=power(P)\times t=1200\ W\times 1800\ s$

$=2.16\times 10^6\ J$

Total energy consumed in the month of April$(30\ days)=2.16\times10^6\times 30\ W$

$=6.48\times10^7\ J$

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Updated on: 10-Oct-2022

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