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Find First element in AP which is multiple of given Prime in Python
Suppose we have a first term (A) and common difference (d) of an AP series, and we also have a prime number P, we have to find the position of the first element in the given AP which is the a multiple of the given prime number P.
So, if the input is like A = 3, D = 4, P = 5, then the output will be 3 as fourth term of the given AP is a multiple of the prime number 5. So, first term = 3, second term = 3+4 = 7, third term = 3+2*4 = 11 and fourth term = 3+3*4 = 15.
To solve this, we will follow these steps −
Define a function get_pow() . This will take x, y, p
ans := 1
x := x mod p
while y > 0, do
if y AND 1 is non-zero, then
ans :=(ans * x) mod p
y := y/2
x :=(x * x) mod p
return ans
From the main method, do the following −
A := A mod P
D := D mod P
if A is same as 0, then
return 0
otherwise when D is same as 0, then
return -1
otherwise,
X := get_pow(D, P - 2, P)
return(X *(P - A)) mod P
Example
Let us see the following implementation to get better understanding −
def get_pow(x, y, p) : ans = 1 x = x % p while y > 0 : if y & 1 : ans = (ans * x) % p y = y >> 1 x = (x * x) % p return ans def get_nearest(A, D, P) : A %= P D %= P if A == 0 : return 0 elif D == 0 : return -1 else : X = get_pow(D, P - 2, P) return (X * (P - A)) % P A = 3 D = 4 P = 5 print(get_nearest(A, D, P))
Input
A = 3 D = 4 P = 5
Output
3
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