Program to find all prime factors of a given number in sorted order in Python

Python Server Side Programming Programming

Suppose we have a number n greater than 1, we have to find all of its prime factors and return them in sorted sequence. We can write out a number as a product of prime numbers, they are its prime factors. And the same prime factor may occur more than once.

So, if the input is like 42, then the output will be [2, 3, 7].

To solve this, we will follow these steps −

res:= a new list
while n mod 2 is same as 0, do
- insert 2 at the end of res
- n := quotient of n/2
for i in range 3 to (square root of n), increase in step 2
- while n mod i is same as 0, do
  - insert i at the end of res
  - n := quotient of n/i
if n > 2, then
- insert n at the end of res
return res

Let us see the following implementation to get better understanding −

Example

Live Demo

class Solution:
   def solve(self, n):
      res=[]
      while n%2==0:
         res.append(2)
         n//=2
      for i in range(3,int(n**.5)+1,2):
         while n%i==0:
            res.append(i)
            n//=i
      if n>2:
         res.append(n)
      return res
ob = Solution()
print(ob.solve(42))

Input

Output

[2, 3, 7]

Arnab Chakraborty

Updated on 07-Oct-2020 13:20:24

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