# Find elements of an Array which are Odd and Even using STL in C++

C++Server Side ProgrammingProgramming

Given with an array and the task is to find the number of odd and even elements in an array using standard template library in C++.

To solve this problem we are using the function count_if() present in C++ standard template library. What is a count_if() function?

## Syntax

count_if(LowerBound, UpperBound, function)

Description − This function returns the number of elements in an array that satisfies the given condition. It takes three parameters.

• Lower Bound − It points to the first element of an array or any other sequence.
• Upper Bound − It points to the last element of an array or any other sequence.
• Function − It returns the Boolean value on the basis of the condition specified.

## Example

Input-: array[] = {2, 4, 1, 5, 8, 9}
Output-: Odd elements are: 1, 5 and 9. So, total number of odds is 3
Even elements are: 2, 4 and 8
Input-: array[] = {1, 2, 3, 4, 5, 10}
Output-: Odd elements are: 1, 3 and 5. So, total number of odds is 3
Even elements are: 2, 4 and 10. So, total number of evens is 3

Approach used in the below program is as follows

• Input the integer values in an array of integer type
• Create the bool function to check whether the element of an array is odd or not. If the selected elements are odd than the remaining elements will be even.
• Call the function count_if() which takes the first and the last element and the function as the parameter.

## Example

Live Demo

#include <bits/stdc++.h>
using namespace std;
// Function to check if the element is odd or even
bool check(int i) {
if (i % 2 != 0)
return true;
else
return false;
}
int main() {
int arr[] = { 2, 10, 1, 3, 7, 4, 9 };
int size = sizeof(arr) / sizeof(arr);
int temp = count_if(arr, arr + size, check);
cout << "Odds are : " <<temp << endl;
cout << "Evens are : " << (size - temp) << endl;
return 0;
}

## Output

If we run the above code it will generate the following output −

Odds are: 4
Evens are: 3