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How to find the Odd and Even numbers in an Array in java?
In the loop check, the result of i%2 operation on each element if 0 the element is even else the element is odd.
Example
public class OddNumbersInAnArray {
public static void main(String args[]) {
int[] myArray = {23, 93, 56, 92, 39};
System.out.println("Even numbers in the given array are:: ");
for (int i=0; i<myArray.length; i++) {
if(myArray[i]%2 == 0) {
System.out.println(myArray[i]);
}
}
System.out.println("Odd numbers in the given array are:: ");
for (int i=0; i<myArray.length; i++) {
if(myArray[i]%2 != 0) {
System.out.println(myArray[i]);
}
}
}
}Output
Even numbers in the given array are:: 56 92 Odd numbers in the given array are:: 23 93 39
Updated on: 19-Feb-2020
2K+ Views
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