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Given with an array and the task is to find the number which are divisible by N using standard template library in C++.

To solve this problem we are using the function count_if() present in C++ standard template library.

**What is a count_if() function?**

count_if(LowerBound, UpperBound, function)

**Description** − This function returns the number of elements in an array that satisfies the given condition. It takes three parameters.

**Lower Bound**− It points to the first element of an array or any other sequence.**Upper Bound**− It points to the last element of an array or any other sequence.**Function**− It returns the Boolean value on the basis of the condition specified.

Input-: array[] = {2, 4, 1, 5, 8, 9} N = 4 Output-: Elements divisible by 4: 2 Input-: array[] = {1, 2, 3, 4, 5, 10} N = 2 Output: Elements divisible by 2: 3

**Approach used in the below program is as follows** −

- Input the integer values in an array of integer type.
- Create the bool function to check whether the element of an array is divisible by the user input value N.
- Call the function count_if() which takes the first and the last element and the function as the parameter.

#include <bits/stdc++.h> using namespace std; int n; //function to check if the element is divisible by n bool check(int i) { if (i % n == 0) return true; else return false; } int main() { int arr[] = {2, 4, 1, 5, 8, 9}; n = 4; int size = sizeof(arr) / sizeof(arr[0]); int temp = count_if(arr, arr + size, check); cout<<"Elements divisible by "<<n<< ": " <<temp; return 0; }

If we run the above code it will generate the following output −

Elements divisible by 4: 2

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