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Count number of even and odd elements in an array in C++
In this tutorial, we will be discussing a program to find the number of even and odd elements in an array.
For this we will be provided with an array. Our task is to calculate the number of even and odd elements in the given array.
Example
#include<iostream>
using namespace std;
void CountingEvenOdd(int arr[], int arr_size){
int even_count = 0;
int odd_count = 0;
//looping through the elements
for(int i = 0 ; i < arr_size ; i++) {
//checking if the number is odd
if (arr[i]%2 != 0)
odd_count ++ ;
else
even_count ++ ;
}
cout << "Number of even elements = " << even_count
<< "
Number of odd elements = " << odd_count ;
}
int main(){
int arr[] = {2, 3, 4, 5, 6};
int n = sizeof(arr) / sizeof(arr[0]);
CountingEvenOdd(arr, n);
}Output
Number of even elements = 3 Number of odd elements = 2
Updated on 05-Feb-2020 07:53:52
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