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Divide one Hermite series by another in Python
To divide one Hermite series by another, use the polynomial.hermite.hermdiv() method in Python Numpy. The method returns an array of Hermite series coefficients representing the quotient and remainder. Returns the quotient-with-remainder of two Hermite series c1 / c2. The arguments are sequences of coefficients from lowest order “term” to highest, e.g., [1,2,3] represents the series P_0 + 2*P_1 + 3*P_2. The parameters, c1 and c2 are 1-D arrays of Hermite series coefficients ordered from low to high.
Steps
At first, import the required library −
import numpy as np from numpy.polynomial import hermite as H
Create 1-D arrays of Hermite series coefficients −
c1 = np.array([53., 30., 52., 7., 6.]) c2 = np.array([1, 2, 3])
Display the arrays of coefficients −
print("Array1...\n",c1)
print("\nArray2...\n",c2)Display the datatype −
print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)Check the Dimensions of both the arrays −
print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)Check the Shape of both the arrays −
print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)To divide one Hermite series by another, use the polynomial.hermite.hermdiv() method in Python Numpy −
print("\nResult (division)....\n",H.hermdiv(c1, c2))Example
import numpy as np
from numpy.polynomial import hermite as H
# Create 1-D arrays of Hermite series coefficients
c1 = np.array([53., 30., 52., 7., 6.])
c2 = np.array([1, 2, 3])
# Display the arrays of coefficients
print("Array1...\n",c1)
print("\nArray2...\n",c2)
# Display the datatype
print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)
# Check the Dimensions of both the arrays
print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)
# Check the Shape of both the arrays
print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)
# To divide one Hermite series by another, use the polynomial.hermite.hermdiv() method in Python Numpy
print("\nResult (division)....\n",H.hermdiv(c1, c2))Output
Array1... [53. 30. 52. 7. 6.] Array2... [1 2 3] Array1 datatype... float64 Array2 datatype... int64 Dimensions of Array1... 1 Dimensions of Array2... 1 Shape of Array1... (5,) Shape of Array2... (3,) Result (division).... (array([0., 1., 2.]), array([1., 1.]))
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