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Multiply a Hermite series by an independent variable in Python
To multiply the Hermite series by x, where x is the independent variable, use the polynomial.hermite.hermmulx() method in Python Numpy. The method returns an array representing the result of the multiplication. The parameter, c is a 1-D array of Hermite series coefficients ordered from low to high.
Steps
At first, import the required library −
import numpy as np from numpy.polynomial import hermite as H
Create an array −
c = np.array([1, 2, 3])
Display the array −
print("Our Array...\n",c)Check the Dimensions −
print("\nDimensions of our Array...\n",c.ndim)Get the Datatype −
print("\nDatatype of our Array object...\n",c.dtype)Get the Shape −
print("\nShape of our Array object...\n",c.shape)To multiply the Hermite series by x, where x is the independent variable, use the polynomial.hermite.hermmulx() method −
print("\nResult....\n",H.hermmulx(c))Example
import numpy as np
from numpy.polynomial import hermite as H
# Create an array
c = np.array([1, 2, 3])
# Display the array
print("Our Array...\n",c)
# Check the Dimensions
print("\nDimensions of our Array...\n",c.ndim)
# Get the Datatype
print("\nDatatype of our Array object...\n",c.dtype)
# Get the Shape
print("\nShape of our Array object...\n",c.shape)
# To multiply the Hermite series by x, where x is the independent variable, use the polynomial.hermite.hermmulx() method in Python Numpy
print("\nResult....\n",H.hermmulx(c))Output
Our Array... [1 2 3] Dimensions of our Array... 1 Datatype of our Array object... int64 Shape of our Array object... (3,) Result.... [2. 6.5 1. 1.5]
Updated on: 01-Mar-2022
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