Divide one Hermite_e series by another in Python


To divide one Hermite_e series by another, use the polynomial.hermite.hermediv() method in Python Numpy. The method returns an array of Hermite_e series coefficients representing the quotient and remainder.

Returns the quotient-with-remainder of two Hermite_e series c1 / c2. The arguments are sequences of coefficients from lowest order “term” to highest, e.g., [1,2,3] represents the series P_0 + 2*P_1 + 3*P_2. The parameters, c1 and c2 are 1-D arrays of Hermite_e series coefficients ordered from low to high.

Steps

At first, import the required library −

import numpy as np
from numpy.polynomial import hermite as H

Create 1-D arrays of Hermite_e series coefficients −

c1 = np.array([53., 30., 52., 7., 6.])
c2 = np.array([1, 2, 3])

Display the arrays of coefficients −

print("Array1...\n",c1)
print("\nArray2...\n",c2)

Display the datatype −

print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

Check the Dimensions of both the arrays −

print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

Check the Shape of both the arrays −

print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

To divide one Hermite_e series by another, use the polynomial.hermite.hermediv() method in Python Numpy −

print("\nResult (division)....\n",H.hermediv(c1, c2))

Example

import numpy as np
from numpy.polynomial import hermite_e as H

# Create 1-D arrays of Hermite_e series coefficients
c1 = np.array([53., 30., 52., 7., 6.])
c2 = np.array([1, 2, 3])

# Display the arrays of coefficients
print("Array1...\n",c1)
print("\nArray2...\n",c2)

# Display the datatype
print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

# Check the Dimensions of both the arrays
print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

# Check the Shape of both the arrays
print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

# To divide one Hermite_e series by another, use the polynomial.hermite.hermediv() method in Python Numpy
print("\nResult (division)....\n",H.hermediv(c1, c2))

Output

Array1...
   [53. 30. 52. 7. 6.]

Array2...
   [1 2 3]

Array1 datatype...
float64

Array2 datatype...
int64

Dimensions of Array1...
1

Dimensions of Array2...
1

Shape of Array1...
(5,)

Shape of Array2...
(3,)

Result (division)....
(array([8., 1., 2.]), array([31., -1.]))

Updated on: 10-Mar-2022

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