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In previous two chapters, we discussed various shift registers & **counters using D flipflops**. Now, let us discuss various counters using T flip-flops. We know that T flip-flop toggles the output either for every positive edge of clock signal or for negative edge of clock signal.

An ‘N’ bit binary counter consists of ‘N’ T flip-flops. If the counter counts from 0 to 2^{𝑁} − 1, then it is called as binary **up counter**. Similarly, if the counter counts down from 2^{𝑁} − 1 to 0, then it is called as binary **down counter**.

There are two **types of counters** based on the flip-flops that are connected in synchronous or not.

- Asynchronous counters
- Synchronous counters

If the flip-flops do not receive the same clock signal, then that counter is called as **Asynchronous counter**. The output of system clock is applied as clock signal only to first flip-flop. The remaining flip-flops receive the clock signal from output of its previous stage flip-flop. Hence, the outputs of all flip-flops do not change (affect) at the same time.

Now, let us discuss the following two counters one by one.

- Asynchronous Binary up counter
- Asynchronous Binary down counter

An ‘N’ bit Asynchronous binary up counter consists of ‘N’ T flip-flops. It counts from 0 to 2^{𝑁} − 1. The **block diagram** of 3-bit Asynchronous binary up counter is shown in the following figure.

The 3-bit Asynchronous binary up counter contains three T flip-flops and the T-input of all the flip-flops are connected to ‘1’. All these flip-flops are negative edge triggered but the outputs change asynchronously. The clock signal is directly applied to the first T flip-flop. So, the output of first T flip-flop **toggles** for every negative edge of clock signal.

The output of first T flip-flop is applied as clock signal for second T flip-flop. So, the output of second T flip-flop toggles for every negative edge of output of first T flip-flop. Similarly, the output of third T flip-flop toggles for every negative edge of output of second T flip-flop, since the output of second T flip-flop acts as the clock signal for third T flip-flop.

Assume the initial status of T flip-flops from rightmost to leftmost is $Q_{2}Q_{1}Q_{0}=000$. Here, $Q_{2}$ & $Q_{0}$ are MSB & LSB respectively. We can understand the **working** of 3-bit asynchronous binary counter from the following table.

No of negative edge of Clock | Q_{0}(LSB) |
Q_{1} |
Q_{2}(MSB) |
---|---|---|---|

0 | 0 | 0 | 0 |

1 | 1 | 0 | 0 |

2 | 0 | 1 | 0 |

3 | 1 | 1 | 0 |

4 | 0 | 0 | 1 |

5 | 1 | 0 | 1 |

6 | 0 | 1 | 1 |

7 | 1 | 1 | 1 |

Here $Q_{0}$ toggled for every negative edge of clock signal. $Q_{1}$ toggled for every $Q_{0}$ that goes from 1 to 0, otherwise remained in the previous state. Similarly, $Q_{2}$ toggled for every $Q_{1}$ that goes from 1 to 0, otherwise remained in the previous state.

The initial status of the T flip-flops in the absence of clock signal is $Q_{2}Q_{1}Q_{0}=000$. This is incremented by one for every negative edge of clock signal and reached to maximum value at 7^{th} negative edge of clock signal. This pattern repeats when further negative edges of clock signal are applied.

An ‘N’ bit Asynchronous binary down counter consists of ‘N’ T flip-flops. It counts from 2^{𝑁} − 1 to 0. The **block diagram** of 3-bit Asynchronous binary down counter is shown in the following figure.

The block diagram of 3-bit Asynchronous binary down counter is similar to the block diagram of 3-bit Asynchronous binary up counter. But, the only difference is that instead of connecting the normal outputs of one stage flip-flop as clock signal for next stage flip-flop, connect the **complemented outputs** of one stage flip-flop as clock signal for next stage flip-flop. Complemented output goes from 1 to 0 is same as the normal output goes from 0 to 1.

Assume the initial status of T flip-flops from rightmost to leftmost is $Q_{2}Q_{1}Q_{0}=000$. Here, $Q_{2}$ & $Q_{0}$ are MSB & LSB respectively. We can understand the **working** of 3-bit asynchronous binary down counter from the following table.

No of negative edge of Clock | Q_{0}(LSB) |
Q_{1} |
Q_{2}(MSB) |
---|---|---|---|

0 | 0 | 0 | 0 |

1 | 1 | 1 | 1 |

2 | 0 | 1 | 1 |

3 | 1 | 0 | 1 |

4 | 0 | 0 | 1 |

5 | 1 | 1 | 0 |

6 | 0 | 1 | 0 |

7 | 1 | 0 | 0 |

Here $Q_{0}$ toggled for every negative edge of clock signal. $Q_{1}$ toggled for every $Q_{0}$ that goes from 0 to 1, otherwise remained in the previous state. Similarly, $Q_{2}$ toggled for every $Q_{1}$ that goes from 0 to 1, otherwise remained in the previous state.

The initial status of the T flip-flops in the absence of clock signal is $Q_{2}Q_{1}Q_{0}=000$. This is decremented by one for every negative edge of clock signal and reaches to the same value at 8^{th} negative edge of clock signal. This pattern repeats when further negative edges of clock signal are applied.

If all the flip-flops receive the same clock signal, then that counter is called as **Synchronous counter**. Hence, the outputs of all flip-flops change (affect) at the same time.

Now, let us discuss the following two counters one by one.

- Synchronous Binary up counter
- Synchronous Binary down counter

An ‘N’ bit Synchronous binary up counter consists of ‘N’ T flip-flops. It counts from 0 to 2^{𝑁} − 1. The **block diagram** of 3-bit Synchronous binary up counter is shown in the following figure.

The 3-bit Synchronous binary up counter contains three T flip-flops & one 2-input AND gate. All these flip-flops are negative edge triggered and the outputs of flip-flops change (affect) synchronously. The T inputs of first, second and third flip-flops are 1, $Q_{0}$ & $Q_{1}Q_{0}$ respectively.

The output of first T flip-flop **toggles** for every negative edge of clock signal. The output of second T flip-flop toggles for every negative edge of clock signal if $Q_{0}$ is 1. The output of third T flip-flop toggles for every negative edge of clock signal if both $Q_{0}$ & $Q_{1}$ are 1.

An ‘N’ bit Synchronous binary down counter consists of ‘N’ T flip-flops. It counts from 2^{𝑁} − 1 to 0. The **block diagram** of 3-bit Synchronous binary down counter is shown in the following figure.

The 3-bit Synchronous binary down counter contains three T flip-flops & one 2-input AND gate. All these flip-flops are negative edge triggered and the outputs of flip-flops change (affect) synchronously. The T inputs of first, second and third flip-flops are 1, ${Q_{0}}'$ &' ${Q_{1}}'$${Q_{0}}'$ respectively.

The output of first T flip-flop **toggles** for every negative edge of clock signal. The output of second T flip-flop toggles for every negative edge of clock signal if ${Q_{0}}'$ is 1. The output of third T flip-flop toggles for every negative edge of clock signal if both ${Q_{1}}'$ & ${Q_{0}}'$ are 1.

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