C++ Program to Implement Gauss Seidel Method


Gauss Seidel method is used to solve linear system of equations in iterative method. This is a C++ Program to Implement Gauss Seidel Method.

Algorithm

Begin
   Take the dimensions of the matrix p and its elements as input.
   Take the initials values of x and no of iteration q as input.
   While q>0
      Make a for loop i = 0 to p-1
         initialize n[i] = (b[i] / a[i][i]).
            Make a for loop i = 0 to p-1
            If (j == i)
               n[i] = n[i] - ((a[i][j] / a[i][i]) * m[j]).
               m[i] = n[i].
      Decrease q.
   /*
      Here, a[i][j] = input matrix.
      b[i] = this array takes values of the right side of equation.
      m[i] = stores initial values of x.
   */
   Return 0
End

Example

#include<iostream>
#include<conio.h>
using namespace std;
int main(void) {
   float a[10][10], b[10], m[10], n[10];
   int p = 0, q = 0, i = 0, j = 0;
   cout << "Enter size of 2D array : ";
   cin >> p;
   for (i = 0; i < p; i++) {
      for (j = 0; j < p; j++) {
         cout << "a[" << i << ", " << j << " ]=";
         cin >> a[i][j];
      }
   }
   cout << "\nEnter values to the right side of equation\n";
   for (i = 0; i < p; i++) {
      cout << "b[" << i << ", " << j << " ]=";
      cin >> b[i];
   }
   cout << "Enter initial values of x\n";
   for (i = 0; i < p; i++) {
      cout << "x:[" << i<<"]=";
      cin >> m[i];
   }
   cout << "\nEnter the no. of iteration : ";
   cin >> q;
   while (q> 0) {
      for (i = 0; i < p; i++) {
         n[i] = (b[i] / a[i][i]);
         for (j = 0; j < p; j++) {
            if (j == i)
               continue;
            n[i] = n[i] - ((a[i][j] / a[i][i]) * m[j]);
            m[i] = n[i];
         }
         cout<<"x"<<i + 1 << "="<<n[i]<<" ";
      }
      cout << "\n";
      q--;
   }
   return 0;
}

Output

Enter size of 2D array : 2
a[0, 0 ]=1
a[0, 1 ]=2
a[1, 0 ]=3
a[1, 1 ]=4

Enter values to the right side of equation
b[0, 2 ]=1
b[1, 2 ]=2
Enter initial values of x
x:[0]=0
x:[1]=0

Enter the no. of iteration : 3
x1 = 1. x2 = -0.25
x1 = 1.5 x2 = -0.625
x1 = 2.25 x2 = -1.1875

Updated on: 30-Jul-2019

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