# C# program to implement FizzBuzz

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Implementation of FizzBuzz involves printing numbers from 1 to 100. If the numbers are multiples of 3 then Fizz is printed. If they are multiples of 5, then Buzz is printed and if they are multiples of both 3 and 5 then FizzBuzz is printed.

A program that demonstrates the implementation of FizzBuzz is given as follows.

## Example

Live Demo

using System;
namespace FizzBuzzDemo {
public class example {
static void Main(string[] args) {
for (int i = 1; i <= 100; i++) {
if (i % 3 == 0 && i % 5 == 0) {
Console.WriteLine("FizzBuzz");
} else if (i % 3 == 0) {
Console.WriteLine("Fizz");
} else if (i % 5 == 0) {
Console.WriteLine("Buzz");
} else {
Console.WriteLine(i);
}
}
}
}
}

## Output

The output of the above program is as follows.

1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz
16
17
Fizz
19
Buzz
Fizz
22
23
Fizz
Buzz
26
Fizz
28
29
FizzBuzz
31
32
Fizz
34
Buzz
Fizz
37
38
Fizz
Buzz
41
Fizz
43
44
FizzBuzz
46
47
Fizz
49
Buzz
Fizz
52
53
Fizz
Buzz
56
Fizz
58
59
FizzBuzz
61
62
Fizz
64
Buzz
Fizz
67
68
Fizz
Buzz
71
Fizz
73
74
FizzBuzz
76
77
Fizz
79
Buzz
Fizz
82
83
Fizz
Buzz
86
Fizz
88
89
FizzBuzz
91
92
Fizz
94
Buzz
Fizz
97
98
Fizz
Buzz

Now, let us understand the above program.

A for loop runs from 1 to 100 and creates the numbers required. Then a series of if statements are used to find if the number i is divisible by 3, by 5 or by both. If the number is only divisible by 3, Fizz is printed. If the number is only divisible by 5, Buzz is printed and if the number is divisible by both, then FizzBuzz is printed. Otherwise, the number is printed. The code snippet for this is as follows −

for (int i = 1; i <= 100; i++) {
if (i % 3 == 0 && i % 5 == 0) {
Console.WriteLine("FizzBuzz");
}else if (i % 3 == 0) {
Console.WriteLine("Fizz");
} else if (i % 5 == 0) {
Console.WriteLine("Buzz");
} else {
Console.WriteLine(i);
}
}
Updated on 20-Apr-2020 08:06:26