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C++ program to find n-th term of series 2, 10, 30, 68, 130 …
In this problem, we are given an integer N. The task is to find the n-th term in series 2, 10, 30, 68, 130...
Let’s take an example to understand the problem,
Input
N = 7
Output
350
Explanation
The series is 2, 10, 30, 68, 130, 222, 350...
Solution Approach
A simple solution to the problem is by finding the general term of the series. Here, the Nth term of the series is N^3 + N. This is found by subtracting the current element with the current index.
For i, i = 1, T(1) = 2 = 1 + 1 = 1^3 + 1 i = 2, T(1) = 10 = 8 + 2 = 2^3 + 2 i = 3, T(1) = 30 = 27 + 3 = 3^3 + 2
Program to illustrate the working of our solution,
Example
#include <iostream> using namespace std; int findNthTerm(int N) { return ((N*N*N) + N); } int main() { int N = 8; cout<<"The "<<N<<"th term of the series is "<<findNthTerm(N); return 0; }
Output
The 8th term of the series is 520
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