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# C/C++ Program to Find sum of Series with n-th term as n power of 2 - (n-1) power of 2

Here we will see how to get the sum of the series with n-th term as n2 – (n-1)2. The recurrence relation is like below −

T_{n} = n^{2} − (n−1)^{2}

So the series is −

We need to find S mod (10^{9} + 7), where S is the sum of all terms of the given series.

## Example

#include<iostream> #define X 1000000007 using namespace std; long long getSum(long long n) { return ((n % X) * (n % X)) % X; } int main() { long long n = 56789; cout << getSum(n); }

## Output

224990500

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