# Converting digits to word format using switch case in C language

## Problem

Is it possible to convert the given one or two-digit numbers into English words by using the C Programming language?

## Solution

We can easily convert the given two-digit number into English word format with the help of a switch case. Not only two digits, but any number can also convert into English like a statement in C.

In this program, we will convert one or two-digit numbers into English word format.

## Example

Live Demo

#include<stdio.h>
int main(){
int no;
printf("enter any 1 or 2 digit number:");
scanf("%d",&no);
if(no<0 || no>=99) //finding out whether enter no is 2 digit or not
printf("Invalid number");
else{
printf("entered number:");
switch(no){
case 0:printf("zero");
break;
case 10: printf("ten");
break;
case 11: printf("eleven");
break;
case 12: printf("twelve");
break;
case 13: printf("thirteen");
break;
case 14: printf("fourteen");
break;
case 15: printf("fifteen");
break;
case 16: printf("sixteen");
break;
case 17: printf("seventeen");
break;
case 18: printf("eighteen");
break;
case 19: printf("nineteen");
break;
default: switch(no/10) //first digit word{
case 2: printf("twenty");
break;
case 3: printf("thirty");
break;
case 4: printf("forty");
break;
case 5: printf("fifty");
break;
case 6: printf("sixty");
break;
case 7: printf("seventy");
break;
case 8: printf("eighty");
break;
case 9: printf("ninty");
break;
}
switch(no%10) //second digit word{
case 1: printf("one");
break;
case 2: printf("tw0");
break;
case 3: printf("three");
break;
case 4: printf("four");
break;
case 5: printf("five");
break;
case 6: printf("six");
break;
case 7: printf("seven");
break;
case 8: printf("eight");
break;
case 9: printf("nine");
break;
}
}
}
}

## Output

enter any 1 or 2 digit number:83
entered number:eightythree

enter any 1 or 2 digit number:6
entered number:six

enter any 1 or 2 digit number:548
Invalid number

Updated on: 05-Mar-2021

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