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Explain switch statement in C language
It is used to select one among multiple decisions. ‘switch’ successively tests a value against a list of integers (or) character constant. When a match is found, the statement (or) statements associated with that value are executed.
Syntax
The syntax is given below −
switch (expression){
case value1 : stmt1;
break;
case value2 : stmt2;
break;
- - - - - -
default : stmt – x;
}Algorithm
Refer the algorithm given below −
Step 1: Declare variables. Step 2: Read expression variable. Step 3: Switch(expression) If value 1 is select : stmt 1 executes break (exists from switch) If value 2 is select : stmt 2 executes ;break If value 3 is select : stmt 3 executes; break …………………………………………… Default : stmt-x executes;
Example
The following C program demonstrates the usage of switch statement −
#include<stdio.h>
main ( ){
int n;
printf ("enter a number");
scanf ("%d", &n);
switch (n){
case 0 : printf ("zero");
break;
case 1 : printf ("one");
break;
default : printf ("wrong choice");
}
}Output
You will see the following output −
enter a number 1 One
Consider another program on switch case as mentioned below −
Example
#include<stdio.h>
int main(){
char grade;
printf("Enter the grade of a student:
");
scanf("%c",&grade);
switch(grade){
case 'A': printf("Distiction
");
break;
case 'B': printf("First class
");
break;
case 'C': printf("second class
");
break;
case 'D': printf("third class
");
break;
default : printf("Fail");
}
printf("Student grade=%c",grade);
return 0;
}Output
You will see the following output −
Run 1:Enter the grade of a student:A Distiction Student grade=A Run 2: Enter the grade of a student:C Second class Student grade=C
Updated on: 15-Mar-2021
6K+ Views
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