Write a C program of library management system using switch case


Problem

How to store the books-related information of library using C programming.

Algorithm

Step 1: Declare a structure which holds data members
Step 2: declare variables which are used for loop
Step 3: use switch case to work on each module
Step 4: case 1- for Adding book information
        Case 2- for Display book information
        Case 3- for Finding number for books in library
        Case 4- for EXIT

Program

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
#include<string.h>
struct library{
   char bookname[50];
   char author[50];
   int noofpages;
   float price;
};
int main(){
   struct library lib[100];
   char bookname[30];
   int i,j, keepcount;
   i=j=keepcount = 0;
   while(j!=6){
      printf("
1. Add book information
");       printf("2.Display book information
");       printf("3. no of books in the library
");       printf("4. Exit");       printf ("

Enter one of the above : ");       scanf("%d",&j);       switch (j){          /* Add book */          case 1:             printf ("Enter book name = ");             scanf ("%s",lib[i].bookname);             printf ("Enter author name = ");             scanf ("%s",lib[i].author);             printf ("Enter pages = ");             scanf ("%d",&lib[i].noofpages);             printf ("Enter price = ");             scanf ("%f",&lib[i].price);             keepcount++;             i++;             break;          case 2:             printf("you have entered the following information
");             for(i=0; i<keepcount; i++){                printf ("book name = %s
",lib[i].bookname);                printf ("\t author name = %s
",lib[i].author);                printf ("\t pages = %d
",lib[i].noofpages);                printf ("\t price = %f
",lib[i].price);             }             break;          case 3:             printf("
No of books in library : %d", keepcount);             break;          case 4:             exit (0);       }    }    return 0; }

Output

1. Add book information
2.Display book information
3. no of books in the library
4. Exit

Enter one of the above : 1
Enter book name = HarryPotter
Enter author name = hp
Enter pages = 250
Enter price = 350.6

1. Add book information
2.Display book information
3. no of books in the library
4. Exit

Enter one of the above : 2
you have entered the following information
book name = HarryPotter
         author name = hp
         pages = 250
         price = 350.600006

1. Add book information
2.Display book information
3. no of books in the library
4. Exit

Enter one of the above : 3

No of books in library : 1
1. Add book information
2.Display book information
3. no of books in the library
4. Exit

Enter one of the above : 4

Updated on: 05-Mar-2021

7K+ Views

Kickstart Your Career

Get certified by completing the course

Get Started
Advertisements