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Convert BST to Max Heap in C++
In this tutorial, we will be discussing a program to convert a binary search tree to a max heap.
For this we will be provided with a binary search tree. Our task is to convert the given binary search tree into a max heap such that following the condition of the binary search tree when elements are compared with themselves.
Example
#include <bits/stdc++.h> using namespace std; //node structure of BST struct Node { int data; Node *left, *right; }; //node creation struct Node* getNode(int data) { struct Node* newNode = new Node; newNode->data = data; newNode->left = newNode->right = NULL; return newNode; } //performing post order traversal void postorderTraversal(Node*); //moving in a sorted manner using inorder traversal void inorderTraversal(Node* root, vector<int>& arr) { if (root == NULL) return; inorderTraversal(root->left, arr); arr.push_back(root->data); inorderTraversal(root->right, arr); } void convert_BSTHeap(Node* root, vector<int> arr, int* i){ if (root == NULL) return; convert_BSTHeap(root->left, arr, i); convert_BSTHeap(root->right, arr, i); //copying data from array to node root->data = arr[++*i]; } //converting to max heap void convert_maxheap(Node* root) { vector<int> arr; int i = -1; inorderTraversal(root, arr); convert_BSTHeap(root, arr, &i); } //printing post order traversal void postorderTraversal(Node* root) { if (!root) return; postorderTraversal(root->left); postorderTraversal(root->right); cout << root->data << " "; } int main() { struct Node* root = getNode(4); root->left = getNode(2); root->right = getNode(6); root->left->left = getNode(1); root->left->right = getNode(3); root->right->left = getNode(5); root->right->right = getNode(7); convert_maxheap(root); cout << "Postorder Traversal:" << endl; postorderTraversal(root); return 0; }
Output
Postorder Traversal: 1 2 3 4 5 6 7
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