# Decimal to Binary conversion

A decimal number can also be converted into its binary form. To convert a decimal number to binary number, we need to divide the number by 2 until it reaches 0 or 1. And in each step, the remainder are stored separately to form the binary equivalent number in reverse order.

In this algorithm, we will follow the recursive approach. It will help us to solve the problem without using stack data structure. In the implementation, we know that recursion of a function will follow the internal stack. We will serve our job by using that stack.

## Input and Output

Input:
Decimal number 56
Output:
Binary Equivalent: 111000

## Algorithm

decToBin(decimal)

Input: Decimal numbers.

Output: Binary equivalent string.

Begin
if decimal = 0 OR 1, then
insert decimal into the binary string
return
decToBin(decimal / 2)
insert (decimal mod 2) into the binary string.
End

## Example

#include<iostream>
using namespace std;

void decToBin(int dec) {
if(dec == 1 || dec == 0) {
cout << dec;          //print either 0 or 1 as dec
return;
}

decToBin(dec/2);    //divide the number by 2 and find decimal again
cout << dec % 2;    //after returning print the value in reverse order
}

main() {
int dec;
cout<<"Enter decimal number: "; cin >> dec;
cout << "Binary Equivalent: "; decToBin(dec);
}

## Output

Enter decimal number: 56
Binary Equivalent: 111000