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Check if a + b = c is valid after removing all zeroes from a, b and c in C++
Suppose we have three numbers a, b, c, we have to check whether a + b = c, after removing all 0s from the numbers or not. Suppose the numbers are a = 102, b = 130, c = 2005, then after removing 0s, the numbers will be a + b = c : (12 + 13 = 25) this is true
We will remove all 0s from a number, then we will check after removing 0s, a + b = c or not.
Example
#include <iostream> #include <algorithm> using namespace std; int deleteZeros(int n) { int res = 0; int place = 1; while (n > 0) { if (n % 10 != 0) { //if the last digit is not 0 res += (n % 10) * place; place *= 10; } n /= 10; } return res; } bool isSame(int a, int b, int c){ if(deleteZeros(a) + deleteZeros(b) == deleteZeros(c)) return true; return false; } int main() { int a = 102, b = 130, c = 2005; if(isSame(a, b, c)) cout << "a + b = c is maintained"; else cout << "a + b = c is not maintained"; }
Output
a + b = c is maintained
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