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C program to find the Roots of Quadratic equation
In this tutorial, we will be discussing a program to find the roots of the Quadratic equation.
Given a quadratic equation of the form ax2 + bx + c. Our task is to find the roots x1 and x2 of the given equation.
For this, we are using the deterministic method, in this
D = √b2 - 4ac
then the roots of the equation will be
x1 = (-b + D)/2a ,and
x2 = (-b - D)/2a
Example
#include<stdio.h> #include<math.h> #include<stdlib.h> //calculating the roots of equation void calc_roots(int a, int b, int c) { if (a == 0) { printf("Invalid Equation"); return; } int d = b*b - 4*a*c; double sqrt_val = sqrt(abs(d)); if (d > 0) { printf("Roots are both real and different \n"); printf("%f\n%f",(double)(-b + sqrt_val)/(2*a) , (double)(-b - sqrt_val)/(2*a)); } else if (d == 0) { printf("Roots are real and same \n"); printf("%f",-(double)b / (2*a)); } else { printf("Roots are complex \n"); printf("%f + i%f\n%f - i%f", -(double)b /(2*a),sqrt_val ,-(double)b / (2*a), sqrt_val); } } int main() { int a = 2, b = -5, c = 8; calc_roots(a, b, c); return 0; }
Output
Roots are complex 1.250000 + i6.244998 1.250000 - i6.244998
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