Java program to find the roots of a quadratic equation

Java8Java Programming Object Oriented Programming

Roots of a quadratic equation are determined by the following formula:

$$x = \frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$$

To calculate the roots −

  • Calculate the determinant value (b*b)-(4*a*c).
  • If determinant is greater than 0 roots are [-b +squareroot(determinant)]/2*a and [-b -squareroot(determinant)]/2*a.
  • If determinant is equal to 0 root value is (-b+Math.sqrt(d))/(2*a)

Example

import java.util.Scanner;
public class RootsOfQuadraticEquation {
   public static void main(String args[]){
      double secondRoot = 0, firstRoot = 0;
      Scanner sc = new Scanner(System.in);
      System.out.println("Enter the value of a ::");
      double a = sc.nextDouble();

      System.out.println("Enter the value of b ::");
      double b = sc.nextDouble();

      System.out.println("Enter the value of c ::");
      double c = sc.nextDouble();

      double determinant = (b*b)-(4*a*c);
      double sqrt = Math.sqrt(determinant);

      if(determinant>0){
         firstRoot = (-b + sqrt)/(2*a);
         secondRoot = (-b - sqrt)/(2*a);
         System.out.println("Roots are :: "+ firstRoot +" and "+secondRoot);
      }else if(determinant == 0){
         System.out.println("Root is :: "+(-b + sqrt)/(2*a));
      }
   }
}

Output

Enter the value of a ::
15
Enter the value of b ::
68
Enter the value of c ::
3
Roots are :: -0.044555558333472335 and -4.488777774999861
raja
Published on 26-Apr-2018 09:12:57
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