Find the quadratic roots in the equation
$4x^{2}-3x+7$

Given:$4x^{2}-3x+7$

To do:  Find real roots of the equation

Solution:

Comparing this to standard quadratic equation $ax^{2} + bx + c = 0$

a = 4; b = -3 and c = 7

Discriminant (D) = $b^{2} - 4ac = (-3)^{2} - 4 \times 4 \times 7$

= 9 - 112

= -103 < 0

So given quadratic has NO REAL ROOTS

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Updated on: 10-Oct-2022

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