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C Program for n-th even number
Given a number N we have to find the N-th even number.
Even numbers are the numbers which are completely divided by 2 and their remainder is zero. Like 2, 4, 6, 8, 10,….
If we closely observe the list of even numbers we can also represent them as
2*1=2, 2*2=4, 2*3=6, 2*4=8,….2*N.
So, to solve the problem we can simply multiply the number N with 2, so the result will be the number which is divisible by 2, i.e. the even number.
Example
Input: n = 4 Output: 8 The first 4 even numbers will be 2, 4, 6, 8, .. Input: n = 10 Output: 20
Algorithm
START STEP 1-> DECLARE AND SET n AS 10 STEP 2-> PRINT n*2 NUMBER STOP
Example
#include <stdio.h> int main(int argc, char const *argv[]){ int n = 10; printf("Nth even will be:%d", n*2); return 0; }
Output
Nth even will be:20
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