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Given a side of a square and the number of fold, we have to find the Area of square after number of folds.

A square is a 2-D shape like rectangle where all the sides are equal. And it’s all angles are equal to 90 degrees.

While folding a square we −

Fold the square from top left side of the triangle to the bottom of the right side forming a triangle.

The second fold will be folding from up to downside.

The third fold is folding again from left to right.

And likewise we follow the above steps.

Input: side = 23, fold = 4 Output: area of square after n folds is : 6.53086

To solve this problem we can follow the below approach −

- Firstly, we have to find the area of a square before folding the square.
- With every fold we have to half the area of the square Area = Area/2.
- Finally we will divide the area of square by pow(2, fold)

START In function double area_nfold(double side, double fold) Step 1-> Decalre and initialize area = side * side Step 2-> Return (area * 1.0 / pow(3, fold)) In int main() Step 1 -> Decalre and initialize double side = 23, fold = 4 Step 2 -> Call function area_nfold(side, fold) and print the results STOP

#include <bits/stdc++.h> using namespace std; //function to calculate area of square after n folds double area_nfold(double side, double fold){ double area = side * side; return area * 1.0 / pow(3, fold); } int main(){ double side = 23, fold = 4; cout <<"area of square after n folds is :"<<area_nfold(side, fold); return 0; }

area of square after n folds is :6.53086

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