# N-th polite number in C++

C++Server Side ProgrammingProgramming

In this tutorial, we are going to write a program that finds the n-th polite number.

A polite number is a positive number that can be written as the sum of 2 or more consecutive positive numbers.

There exists a formula to find the n-th polite number. The formula is n + log2(n + log2(n))

The default log computes with base e. We need to compute using base 2. Divide the default log result with log(2) to get the value of log with base e.

## Example

Let's see the code.

Live Demo

#include <bits/stdc++.h>
using namespace std;
double getNthPoliteNumber(double n) {
n += 1;
return n + (log((n + (log(n) / log(2.0))))) / log(2.0);
}
int main() {
double n = 10;
cout << (int)getNthPoliteNumber(n) << endl;
return 0;
}

## Output

If you run the above code, then you will get the following result.

14

## Conclusion

If you have any queries in the tutorial, mention them in the comment section.

Published on 29-Jun-2021 09:12:36