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C Program for n-th odd number
Given a number N we have to find the N-th odd number.
Odd numbers are the numbers which are not completely divided by 2 and their remainder is not zero. Like 1, 3, 5, 7, 9,….
If we closely observe the list of even numbers we can also represent them as
(2*1)-1=1, (2*2)-1=3,( 2*3)-1=5, (2*4)-1=7,….(2*N)-1.
So, to solve the problem we can simply multiply the number N with 2 and subtract 1 from the result, that makes up an odd number.
Examples
Input: 4 Output: 7 The 4th odd number is 1, 3, 5, 7.. Input: 10 Output: 19
Algorithm
START STEP 1 -> Declare and assign an integer ‘n’. STEP 2 -> Print n*2-1(odd number). STOP
Example
#include <stdio.h>
int main(int argc, char const *argv[]){
int n = 10;
//for odd numbers we can simply subtract 1 to the even numbers
printf("Nth odd number = %d", n*2-1);
return 0;
}Output
Nth odd number = 19
Updated on: 23-Sep-2019
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