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Articles by Arnab Chakraborty
Page 344 of 377
Check if a number is divisible by all prime divisors of another number in C++
Suppose there are two numbers. We have to check whether a number is divisible by all of the prime factors or the second number or not. Suppose a number is 120. The prime factors are {2, 3, 5}, another number is 75, here the prime factors are {3, 5}. As 120 is divisible by 3 and 5 also, then the decision is yes.If one number is 1, then it has no prime divisors, so answer is True. Otherwise we have to find the GCD of these two numbers. If GCD is 1, then they are co-prime. So answer is false. ...
Read MoreCheck if a number is Bleak in C++
Here we will see whether a number is Bleak or not. A number is said to be bleak if it cannot be represented as sum of a positive number x and set bit count in x. So x + set_bit_count(x) is not equal to n , for any non-negative number x.The concept is very simple, if the set bit count + the number is not same as the number, then that is Bleak, otherwise it is not.Example Live Demo#include using namespace std; int set_bit_count(int x) { unsigned int bit_count = 0; while (x != 0) { ...
Read MoreCheck if a linked list is Circular Linked List in C++
Here we will see, hoe to check a linked list is circular linked list or not. To check whether the linked list is circular or not, we will store the header node into some other variable, then traverse the list, if we get null at the next part of any node, then that is not circular, otherwise we will check the next node is same as the stored node or not, if so then that is circular.Example Live Demo#include using namespace std; class Node{ public: int data; Node *next; }; Node* getNode(int data){ Node *newNode = ...
Read MoreCheck if a large number is divisible by 13 or not in C++
Here we will see how to check a number is divisible by 13 or not. In this case the number is very large number. So we put the number as string.A number will be divisible by 13, if the number satisfies the following situations −A number is divisible by 13 if and only if we get the alternating sum i.e. alternatively adding and subtracting of blocks of three numbers from right to left is divisible by 13. For example, 2911285 is divisible by 13 because the alternating sum of blocks of size 3 is 2 – 911 + 285 = ...
Read MoreCheck if a large number can be divided into two or more segments of equal sum in C++
Here we will see a program, that can check whether a number can be divided into more than one segments with equal sum. Suppose a number is like 74325, then this can be segmented into three parts (7), (4, 3), (2, 5), all are of same um value.We have to follow these steps to solve this problem.Take the number as stringuse an array to hold prefix sum of the arrayNow traversing from second element to last element, and the first segment will be 0 to i-1, whose sum will be placed at prefix_sum[i - 1]Use another variable which traverses from ...
Read MoreCheck if a given number is Pronic in C++
Here we will see, how to check whether a number is Pronic number or not. A number that can be arranged to form a rectangle, are called the pronic numbers. First few pronic numbers are: 0, 2, 6, 12, 20, 30, 42, 56, 72, 90, 110, 132, 156, 182, 210, 240, 272, 306, 342. The pronin numbers are product of two consecutive integers. So a pronic number n = x * (x + 1).Here we will check and generate some pronic numbers.Example Live Demo#include #include using namespace std; bool isPronicNumber(int num) { for (int i = 0; i
Read MoreCheck if a given number divides the sum of the factorials of its digits in C++
Suppose, we have an integer, we have to find if the number divides the sum of the factorial of its digits. Suppose a number is 19, the sum of factorial of digits is (1! + 9!) = 362881, this is divisible by 19.To solve this, we will take the number, then calculate factorial of each digit and add the sum, if the sum is divisible by the number itself, then return true, otherwise false.Example#include using namespace std; int factorial(int n){ if(n == 1 || n == 0) return 1; return factorial(n - 1) * ...
Read MoreCheck if a given number can be represented in given a no. of digits in any base in C++
Suppose we have a number n, and number of digits d. We have to check whether the number n can be represented as d digit number in any base from 2 to 32. Suppose the number n is 8, and d = 4, then this can be represented as 1000 in binary, here the d is 4.The idea is to check all bases one by one from 2 to 32. We can follow these steps to check the base.If the number is smaller than base, and digit is 1, then return trueif digit is more than one and number is ...
Read MoreCheck if a given mobile number is fancy in C++
We have a 10 digit mobile number, our task is to check whether the number is fancy number or not. There are three different conditions for a fancy number. If at least one is true, then the number is fancy. These conditions are like below −A single number occurs three consecutive times, like 555Three consecutive numbers are either in increasing or decreasing order like 123 or 321.A single digit occurs four or more times in a number, like 8965499259, here 9 has occurred four times.One example of fancy number is 9859009976, this is a fancy number as the third condition ...
Read MoreCheck if a cell can be visited more than once in a String in C++
Suppose we have a string with dots (.) and a number, a dot indicates the cell is empty, and if there is a number x in any cell, it indicates that we can move x steps to the right or left within the string. Our task is to check whether we can visit a cell more than once or not. For example, if a string is like “. 2 . . . 2 . .”, then we can visit 4th cell in two different ways. From second cell to two step to right, or from two step left from cell ...
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