Arnab Chakraborty

Arnab Chakraborty

3,768 Articles Published

Articles by Arnab Chakraborty

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Longest Substring with At Least K Repeating Characters in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 371 Views

Suppose we have a string s, and we have to find the length of the longest substring T of that given string (consists of lowercase letters only) such that every character in T appears no less than k times. So if the string is “ababbc” and k = 2, then the output will be 3 and longest substring will be “ababb”, as there are two a’s and three b’s.To solve this, we will follow these steps −create one recursive function called longestSubstring(), this takes string s and size kif k = 1, then return the size of the stringif size ...

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Queue Reconstruction by Height in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 427 Views

Consider we have a random list of people standing in a queue. If each person is described by a pair of integers (h, k), where h is the height and k is the number of people in front of him, who have a height greater than or equal to h. We have to define one method to reconstruct the queue. So if the given array is like [[7, 0], [4, 4], [7, 1], [5, 0], [6, 1], [5, 2]], then the output will be [[5, 0], [7, 0], [5, 2], [6, 1], [4, 4], [7, 1]]To solve this, we will ...

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Partition Equal Subset Sum in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 475 Views

Suppose we have a non-empty array containing only positive numbers, we have to find if the array can be partitioned into two subsets such that the sum of elements in both subsets is the same. So if the input is like [1, 5, 11, 5], the output will be true. As this array can be partitioned as [1, 5, 5] and [11]To solve this, we will follow these steps −n := size of the arraysum := 0for i := 0 to n – 1sum := sum + nums[i]if sum is odd, return falsesum := sum / 2create one array called ...

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Word Ladder in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 944 Views

Suppose we have two words (beginWord and endWord), and we have dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that −Only one letter can be converted at a time.In each transformed word must exist in the word list. The beginWord is not a transformed word.We have to keep in mind that −Return 0 when there is no such change sequence.All words have the same length.All words contain only lowercase characters.We can assume no duplicates in the word list.So if the input is like: beginWord = "hit", endWord = "cog", and wordlist = ["hot", ...

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Reconstruct Original Digits from English in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 474 Views

Suppose we have a non-empty string containing an out-of-order English representation of digits 0-9, output the digits in ascending order. There are some properties −Input is guaranteed to be valid and can be transformed to its original digits. That means invalid inputs such as "abc" or "zerone" are not permitted.Input length is less than 50, 000.So if the input is like “fviefuro”, then the output will be 45.To solve this, we will follow these steps −nums := an array that is holding the numbers in English letter from 0 to 9.make one array count of size 10ans := an empty ...

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Longest Repeating Character Replacement in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 2K+ Views

Suppose we have given a string s that consists of only uppercase letters, we can perform at most k operations on that string. In one operation, we can select any character of the string and change it to any other uppercase letters. We have to find the length of the longest sub-string containing all repeating letters we can get after performing the above operations. So if the input is like: “ABAB” and k = 2, then the output will be 4. This is because two ‘A’s with two ‘B’s or vice versa.To solve this, we will follow these steps −maxCount ...

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Add and Search Word - Data structure design in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 550 Views

Suppose we have to design a data structure that supports the following two operations −addWord(word)search(word)The search(word) method can search a literal word or a regular expression string containing only letters a-z or .. A . means it can represent any one letter. So for example, if we add some words like “bad”, “dad”, “mad”, then search for search(“pad”) → false, search(“bad”) → true, search(“.ad”) → true and search(“b..”) → trueTo solve this, we will follow these steps −There are some methods, initially define insertNode(), this will take the head reference and the string s, this will work as follows −curr ...

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Sort Characters By Frequency in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 2K+ Views

Suppose we have a string, we have to sort the characters based on the frequency. So if the string is like “abbbacbcc”, then the output will be “bbbbcccaa”To solve this, we will follow these steps −create an array of pairs called v, create one map mfor all characters in string, increase value of m[character] by 1i := first element of mapwhile map has elementsinsert (i.second, i.first) into vand increase i to point to the next elementsort the vector vans := an empty stringfor i := 0 to size of vt := first element of v[i]while t is not 0ans := ...

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Super Ugly Number in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 403 Views

We have to create one function to find the nth super ugly number. The super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of size k. So if the n is 12 and primes are [2, 7, 13, 19], then the output will be 32, this is because [1, 2, 4, 7, 8, 13, 14, 16, 19, 26, 28, 32] is the sequence of 12 super ugly numbers.To solve this, we will follow these steps −Create a data structure triplet, with num, prime and idxif n is 1, then return 1, create ...

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Target Sum in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 799 Views

Suppose we have a list of non-negative integers, a1, a2, ..., an, and another value, that is target, S. Now we have 2 symbols + and -. For each integer, we should choose one from + and - as its new symbol. we have to find out how many ways to assign symbols to make sum of integers same as the target value S. So if the numbers are [1, 1, 1, 1, 1], and S = 3, then the output will be 5, as the combinations are – 1 + 1 + 1 + 1 + 1 = 3, ...

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