Suppose we have two sorted linked lists, we have to make a linked list that consists of largest sum path from start node to end node. The final list may consist of nodes from both input lists.When we are creating the result list, we may switch to the other input ... Read More

Suppose we have one matrix, we have to convert it to 2d linked list using recursive approach.The list will have the right and down pointer.So, if the input is like102030405060708090then the output will beTo solve this, we will follow these steps −Define a function make_2d_list(), this will take matrix mat, ... Read More

Suppose we have one matrix, we have to convert it to 2d linked list using iterative approach. The list will have the right and down pointer.So, if the input is like102030405060708090then the output will beTo solve this, we will follow these steps −real_head := NULLDefine an array head_arr of size: ... Read More

Suppose we have one size variable N, we also have one variable SUM this is the total sum of all elements available in the array and another variable K such that there is no element in array is greater than K, We have to find one orthogonal array where all ... Read More

Here we will see how we can construct a pandas dataframe using string type data. Pandas supports csv files, but we can do the same using string also. For string type data, we have to use one wrapper, that helps to simulate as the data is taken as csv reader.Here ... Read More

Suppose we have one postorder traversal of a binary search tree; we have to find the binary search tree from it.So, if the input is like [6, 12, 10, 55, 45, 15], then the output willTo solve this, we will follow these steps −Define a function solve() . This will ... Read More

Suppose we have the inorder and postorder traversal sequence of a binary tree. We have to generate the tree from these sequences. So if the postorder and inorder sequences are [9, 15, 7, 20, 3] and [9, 3, 15, 20, 7], then the tree will be −Let us see the ... Read More

Suppose we have the postorder traversal sequence of a binary search tree. We have to generate the tree from these sequences. So, if the postorder sequences is [9, 15, 7, 20, 3], then the tree will be −To form a tree we need inorder traversal also, but for binary search ... Read More

Here we will see the concept of the user-defined literals in C++. From C++ version 11, the User Defined Literals (UDL) are added in C++. C++ also provides literals for a variety of built-in types but these are limited.Built-in Literals −31 (Integer)3.5 (Double)4.2F (Float)'p' (Character)31ULL (Unsigned Long Long)0xD0 (Unsigned Hexadecimal ... Read More

Here we will discuss about the uniform initialization in C++. This is supported from C++11 version. The uniform initialization is a feature that permits the usage of a consistent syntax to initialize variables and objects which are ranging from primitive type to aggregates. In other words, it introduces brace-initialization that ... Read More