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Page 1734 of 2109
Rencontres Number (Counting partial derangements) Using C++
Given two integers N and k, we need to count the number of derangements where k points are fixed at their position. Given constraints on k are between 0 and n as the number of fixed points when there are n points cannot be more than n. int N=4, k=2; res = solve(N, k); Note that at least conditions don’t hold on k. There has to be precisely and strictly k points on their original index. This is a mathematical problem. Not explaining the proof and explanation of mathematics, we as computer science majors can use the results ...
Read MoreRemove Edges Connected to a Node Such That The Three Given Nodes are in Different Trees Using C++
Suppose we are given a binary tree and three nodes in that binary. We have to disconnect one node entirely from the tree. Disconnecting that node leaves us with three different trees. Each of the three given nodes lies in one of them, or each of the given three nodes must not exist in the same tree. Disconnecting a node means that we will remove all the edges from this node to all other nodes. Example For example, let's say we have a tree with three nodes 18, 15, and 17 as shown below − If the task ...
Read MoreC++ program to represent the Fraction of Two Numbers in the String Format
We are given two integer numerators and a denominator. We need to represent the fraction of these two integers in string format. If a certain decimal is repeating, we need a bracket to show its repeating sequence. Algorithm (Steps) Following are the Algorithm/steps to be followed to perform the desired task − Determine the integral quotient (absolute part before to the decimal point) before determining the fractional portion. Insert the remainder (numerator % denominator) in a map with the key being the remainder and the value being the index position at which this remainder occurs to see if ...
Read MoreC++ program to replace an element makes array elements consecutive
We are given an array of elements. We need to find if it is possible to change the value of any one element to make the array elements consecutive. If not possible, return -1 ; otherwise, the element needs to be changed. Let's suppose we have an array {4, 3, 9, 5, 6} and we have to sort this given array. Then start from the smallest and largest element checking the number of mismatches. If the number of mismatches is more than 1 on both sides of the array, the answer is -1. Otherwise, it is possible to get the ...
Read MoreSearching an Element in Doubly Circular Linked List using C++
Given a double circular linked list and key, we have to search the key in the linked list and give a proper message if found. Suppose we have a linked list with the specific characters, and we have to search for an element in it. So let's start with the following linked list − 5 8 9 2 4 We will use 4 as a key to finding the solution to the given problem. A double-linked list has no fixed head, so we will start from any node and then mark that node as ...
Read MoreC++ program to find Second most repeated word in a sequence
We are given an array of words, and we need to find the word whose frequency is the second largest in the array. Let’s assume some simple input and output scenarios Let’s assume we are having an array which consists of elements like [“point, ” “world, ” “articles, ” “articles, ” “articles, ” “world, ” “world, ” “world, ” “point”]. The frequency of words are − “point”: 2 “world”: 4 “articles”: 3 // This will be the second most repeated word in the array. So the second most repeated word is “articles, ” and our output is “articles.” Let’s ...
Read MoreSmallest integer > 1 which divides every element of the given array: Using C++
In this article, we are given integers in an array, and we must find the smallest number which is greater than 1 that divides all the elements in the array. For example, let us consider a sample array [30, 90, 15, 45, 165]. vector arr = {30, 90, 15, 45, 165}; result = solve(arr); Now we can find the array's GCD(greatest common divisor). If it comes out to be 1 that means that only 1 can divide the whole array, and we can return -1 or "Not possible." If it's an integer, then this integer divides the whole ...
Read MoreC++ program to Replace Nodes with Duplicates in Linked List
In this article, we are given a linked list that contains elements from 1 to n and duplicates. Elements 1 to n will always be there with duplicates from [1..n]. We need to replace every duplicate element with n+1, n+2, and so on. Lets consider an example 1→2→2→4→5→3→6→6 Next n = 42. So every duplicate is replaced with n+1, n+2, and so on. The next 42 is replaced with 47, and the next 46 is replaced with 48, leaving the first instance as it is. First of all, we need to construct a binary tree in the main method as ...
Read MoreC++ program to Replace Every Matrix Element with Maximum of GCD of Row or Column
In this method, we need to replace every element in the given matrix with the maximum Greatest Common Divisor (GCD) of that row and column. Let us look at some input scenarios − Suppose we are given a 2D matrix of dimensions m*n is; Input: [[3, 2, 1, 4] [7, 6, 2, 8] [14, 20, 25, 17]]; In the above matrix, row 1 gcd(3, 2, 1, 4) = 1 and Column 2 gcd(3, 7, 14) = 1. So element 2 (1st row and 2nd column) becomes the maximum (1, 1) = 1. So on for all elements and our ...
Read MoreReplace each node with its Surpasser Count in Linked List Using C++
We are given a linked list, and we need to find elements in the given linked list which are greater and present in the right of the current element. The count of these elements needs to be substituted into the current node's value. Let's take a linked list with the following characters and replace each node with its Surpasser count − 4 -> 6 -> 1 -> 4 -> 6 -> 8 -> 5 -> 8 -> 3 From backward, traverse the linked list (so we do not need to worry about elements to the left of the current). ...
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