PHP program to check if a year is leap year or not
To check if a year is leap year or not in PHP, the code is as follows −
Example
Live Demo
<?php
function year_check($my_year)
{
if ($my_year % 400 == 0)
print("It is a leap year");
if ($my_year % 4 == 0)
print("It is a leap year");
else if ($my_year % 100 == 0)
print("It is not a leap year");
else
print("It is not a leap year");
}
$my_year = 2024;
year_check($my_year);
?>Output
It is a leap year
A function named ‘year_check’ is defined that takes a year as a parameter. It checks to see if the year can be divided by 400 or 4 completely, if yes, it means it is a leap year. Otherwise, it is a leap year. The value for year is defined outside the function, and the function is called by passing this year as a parameter to it. Relevant output is displayed on the console.
Published on 02-Jul-2020 10:26:28
