Server Side Programming Articles

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Python program to convert time from 12 hour to 24 hour format

AmitDiwan
AmitDiwan
Updated on 11-Aug-2022 6K+ Views

In this article, we will learn how to convert time from 12 to 24 hours format. Let’s say we have the following input date in 12-hour format − 10:25:30 PM The following is the output in 24-hour format − 22:25:30 Convert current time from 12 hour to 24 hour format To convert time from 12 hour to 24 hour format, here’s the code − Example import datetime def timeconvert(str1): if str1[-2:] == "AM" and str1[:2] == "12": return "00" + str1[2:-2] elif str1[-2:] == "AM": return str1[:-2] elif str1[-2:] == "PM" and str1[:2] == "12": return str1[:-2] ...

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Python program using map function to find row with maximum number of 1's

AmitDiwan
AmitDiwan
Updated on 11-Aug-2022 405 Views

In this article, we will learn how to use map function to find row with maximum number of 1's. 2D array is given and the elements of the arrays are 0 and 1. All rows are sorted. We have to find row with maximum number of 1's. Here we use map (). The map function is the simplest one among Python built-ins used for functional programming. These tools apply functions to sequences and other iterables. Let’s say the input is the following array − [[0, 1, 1, 1, 1], [0, 0, 1, 1, 1], [1, 1, 1, 1, 1], [0, ...

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Python program to count occurrences of an element in a tuple

AmitDiwan
AmitDiwan
Updated on 11-Aug-2022 2K+ Views

We will see how to count occurrences of an element in a Tuple. A tuple is a sequence of immutable Python objects. Let’s say we have the following input, with the occurrences of 20 to be checked − myTuple = (10, 20, 30, 40, 20, 20, 70, 80) The output should be − Number of Occurrences of 20 = 3 Count occurrence of an element in a Tuple using for loop In this example, we will count the occurrences of an element in a Tuple − Example def countFunc(myTuple, a): count = 0 for ele in myTuple: ...

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C++ program to Reorder the Given String to Form a K-Concatenated String

Prateek Jangid
Prateek Jangid
Updated on 10-Aug-2022 204 Views

We are given a string and an integer k, and we need to reorder the characters in the string so that it becomes the concatenation of k similar substring. If not possible, output the result as "Impossible”. string = "malaalam"; K = 2; res = solve(s, K); Example (Using Maps) Let's have a string "mottom" and K=2. The given string can be represented as the concatenation of 2 substrings like tomtom, motmot omtomt, etc. As in all 3, two substrings are joined together when k = 2. Using the string, we can determine how many times each character occurs. ...

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C++ program to Replace Duplicates with Greater than Previous Duplicate Value

Prateek Jangid
Prateek Jangid
Updated on 10-Aug-2022 385 Views

A series of integers is given in this article. Let's say we have an array of four elements without counting the repetitive elements, [2, 2, 5, 5, 7, 8, 7], and we have to make the array distinctive. Changing a value with one that is greater than the previous one is possible. In the above array, element 2 at index 1 becomes 3 as the next greater element. 5 at index 3 becomes 6 as the next greater and so on. So, in the end, our array becomes [2 3 5 6 7 8 9] and should minimize the sum ...

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C++ program to remove row or column wise duplicates from matrix of characters

Prateek Jangid
Prateek Jangid
Updated on 10-Aug-2022 592 Views

We are given a 2D matrix with rows and columns. The matrix consists of elements in char data type. A method is devised to remove the elements which are duplicated in their respective rows or columns. In this method, we check if any element is repeating in its row or column for each character. If it is not repeated, we leave it as it was before. We can store the values occurring in each row and column in a map. After which, we can traverse again and take those values which are appearing only once in their row and column. ...

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Finding the second largest element in BST using C++

Prateek Jangid
Prateek Jangid
Updated on 10-Aug-2022 846 Views

In a binary search tree (BST), the second largest element must be returned. In a binary tree, the second element is the largest element. According to the given BST, 13 is the second largest element. Now we are using the C++ approach to solve this problem. We can traverse the tree inorder, and by observation, we can observe that the second largest element in the given BST is 13. The inorder of the tree will be 1 3 4 6 7 8 10 13 14, and we can observe that the elements are in the sorted array. So we ...

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C++ program to find the shortest distance between two nodes in BST

Prateek Jangid
Prateek Jangid
Updated on 10-Aug-2022 918 Views

In this article, we are given a BST (binary search tree), and we need to find the shortest distance between 2 given nodes in the BST. Let's have a tree and below are the following scenarios. Let’s assume some simple input and output scenarios Now we have to find the distances between nodes 4 and 13. int key1=13, key2=4; res = solve(root, min(key1, key2), max(key1, key2)); output = 6 The shortest distance is 6, which is through 4->6->3->8->10->14->13(the arrows show a path definition and not anything else). Let’s find another distance from two different nodes in the above ...

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C++ program to Replace a Node with Depth in a Binary Tree

Prateek Jangid
Prateek Jangid
Updated on 10-Aug-2022 435 Views

Suppose we have a binary tree and we want to replace the depth of each node with its value. The depth of the node starts from 0 at the root node and increases by 1 for each level we go; for example, we have a binary tree like this; Here we replace, Node Value Depth 1 0 2 1 3 1 4 2 5 2 6 2 7 2 8 3 9 3 We do a simple ...

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Replace Each Node in Binary Tree With The Sum Of Its Inorder Predecessor And Successor Using C++

Prateek Jangid
Prateek Jangid
Updated on 10-Aug-2022 440 Views

We are given a binary tree, and we need to replace all the elements with the sum of its inorder predecessor and successor. Inorder is a traversed path in a graph that reads in the order of left node – root node – right node. The method adds the elements in left and right nodes of the parent node and replaces the value with the obtained sum. Suppose we have a tree with the following formation and characters − We can find and store the inorder of the tree in an array. After that, we can again do an ...

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