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Page 1389 of 2109
Minimum value that divides one number and divisible by other in C++
Problem statementGiven two integer p and q, the task is to find the minimum possible number x such that q % x = 0 and x % p = 0. If the conditions aren’t true for any number, then print -1.ExampleIf p = 3 and q = 66 then answer is 3 as: 66 % 3 = 0 3 % 3 = 0AlgorithmIf a number x satisfies the given condition, then it’s obvious that q will be divided by p i.e. q % p = 0 because x is a multiple of p and q is a multiple of xSo ...
Read MoreMinimum XOR Value Pair in C++
Problem statementGiven an array of integers. Find the pair in an array which has minimum XOR valueExampleIf arr[] = {10, 20, 30, 40} then minimum value pair will be 20 and 30 as (20 ^ 30) = 10. (10 ^ 20) = 30 (10 ^ 30) = 20 (10 ^ 40) = 34 (20 ^ 30) = 10 (20 ^ 40) = 60 (30 ^ 40) = 54AlgorithmGenerate all pairs of given array and compute XOR their valuesReturn minimum XOR valueExample#include using namespace std; int getMinValue(int *arr, int n) { int minValue = INT_MAX; for (int i = 0; i < n; ++i) { for (int j = i + 1; j < n; ++j) { minValue = min(minValue, arr[i] ^ arr[j]); } } return minValue; } int main() { int arr[] = {10, 20, 30, 40}; int n = sizeof(arr) / sizeof(arr[0]); cout
Read MoreMirror of n-ary Tree in C++
Problem statementGiven a Tree where every node contains variable number of children, convert the tree to its mirrorExampleIf n-ary tree is −Then it’s mirror is −Example#include using namespace std; struct node { int data; vectorchild; }; node *newNode(int x) { node *temp = new node; temp->data = x; return temp; } void mirrorTree(node * root) { if (root == NULL) { return; } int n = root->child.size(); if (n < 2) { return; } for (int i = 0; i < n; ...
Read MoreMissing Permutations in a list in C++
Problem statementGiven a list of permutations of any word. Find the missing permutation from the list of permutations.ExampleIf permutation is = { “ABC”, “ACB”, “BAC”, “BCA”} then missing permutations are {“CBA” and “CAB”}AlgorithmCreate a set of all given stringsAnd one more set of all permutationsReturn difference between two setsExample#include using namespace std; void findMissingPermutation(string givenPermutation[], size_t permutationSize) { vector permutations; string input = givenPermutation[0]; permutations.push_back(input); while (true) { string p = permutations.back(); next_permutation(p.begin(), p.end()); if (p == permutations.front()) break; ...
Read MoreMax sum of M non-overlapping subarrays of size K in C++
Problem statementGiven an array and two numbers M and K. We need to find sum of max M subarrays of size K (non-overlapping) in the array. (Order of array remains unchanged). K is the size of subarrays and M is the count of subarray. It may be assumed that size of array is more than m*k. If total array size is not multiple of k, then we can take partial last array.ExampleIf Given array is = {2, 10, 7, 18, 5, 33, 0}. N = 7, M = 3 and K = 1 then output will be 61 as subset ...
Read MoreMinimum operations required to remove an array in C++
DescriptionGiven an array of N integers where N is an even number. There are two kinds of operations allowed on the array.Increase the value of any element of an array by 1.If two adjacent elements in the array are consecutive prime number, delete both the element.The task is to find the minimum number of operations required to remove all the element of the array.ExampleIf array is {10, 13} then minimum 2 operations are requiredIncrement 1st element of an array by 1. So new array becomes {11, 13}Delete 1st and 2nd element as both are consecutive prime numbersAlgorithm1. To remove numbers, ...
Read MoreMinimum operations required to make all the array elements equal in C++
Problem statementGiven an array with n positive integers. We need to find the minimum number of operation to make all elements equal. We can perform addition, multiplication, subtraction or division with any element on an array element.ExampleIf input array is = {1, 2, 3, 4} then we require minimum 3 operations to make all elements equal. For example, we can make elements 4 by doing 3 additions.Algorithm1. Select element with maximum frequency. Let us call it ‘x’ 2. Now we have to perform n-x operations as there are x element with same valueExample#include using namespace std; int getMinOperations(int ...
Read MoreMinimum operations of given type to make all elements of a matrix equal in C++
Problem statementGiven an integer K and a matrix of M x N, the task is to find the minimum number of operations required to make all the elements of the matrix equal. In a single operation, K can be added to or subtracted from any element of the matrix.ExampleIf input matrix is: { {2, 4}, {20, 40} } and K = 2 then total 27 operations required as follows; Matrix[0][0] = 2 + (K * 9) = 20 = 9 operations Matrix[0][1] = 4 + (k * 8) = 20 = 8 operations Matrix[1][0] = 20 + (k ...
Read MoreStein's Algorithm for finding GCD in C++
Stein's Algorithm used for discovering GCD of numbers as it calculates the best regular divisor of two non-negative whole numbers. It replaces division with math movements, examinations, and subtraction. In the event that both an and b are 0, gcd is zero gcd(0, 0) = 0. The algorithm for GCD(a, b) as follows;AlgorithmSTART Step-1: check If both a and b are 0, gcd is zero gcd(0, 0) = 0. Step-2: then gcd(a, 0) = a and gcd(0, b) = b because everything divides 0. Step-3: check If a and b are both even, gcd(a, b) = 2*gcd(a/2, ...
Read MoreMinimum operation to make all elements equal in array in C++
Problem statementGiven an array with n positive integers. We need to find the minimum number of operation to make all elements equal. We can perform addition, multiplication, subtraction or division with any element on an array element.ExampleIf input array is = {1, 2, 3, 4} then we require minimum 3 operations to make all elements equal. For example, we can make elements 4 by doing 3 additions.Algorithm1. Select element with maximum frequency. Let us call it ‘x’ 2. Now we have to perform n-x operations as there are x element with same valueExample#include using namespace std; int getMinOperations(int *arr, int ...
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