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Python Articles
Page 716 of 852
Get last element of each sublist in Python
A list in python can also contain lists inside it as elements. These nested lists are called sublists. In this article we will solve the challenge of retrieving only the last element of each sublist in a given list.Using for loopIt is a very simple approach in which we loop through the sublists fetching the item at index -1 in them. A for loop is used for this purpose as shown below.Example Live DemoAlist = [['Mon', 1], ['Tue', 'Wed', "Fri"], [12, 3, 7]] print("Given List:", Alist) print("Lastst Items from sublists:") for item in Alist: print((item[-1]))OutputRunning the above code gives us ...
Read MoreGet first element of each sublist in Python
A list in python can also contain lists inside it as elements. These nested lists are called sublists. In this article we will solve the challenge of retrieving only the first element of each sublist in a given list.Using for loopIt is a very simple approach in which we loop through the sublists fetching the item at index 0 in them. A for loop is used for this purpose as shown below.Example Live DemoAlist = [['Mon', 1], ['Tue', 'Wed', "Fri"], [12, 3, 7]] print("Given List:", Alist) print("First Items from sublists:") for item in Alist: print((item[0]))OutputRunning the above code gives us ...
Read MoreCount unique sublists within list in Python
A Python list can also contain sublist. A sublist itself is a list nested within a bigger list. In this article we will see how to count the number of unique sublists within a given list.Using CounterCounter is a subclass of Dictionary and used to keep track of elements and their count. It is also considered as an unordered collection where elements are stored as Dict keys and their count as dict value. So in the below example we directly take a list which has sublists.Example Live Demofrom collections import Counter # Given List Alist = [['Mon'], ['Tue', 'Wed'], ['Tue', 'Wed']] ...
Read MoreAssign ids to each unique value in a Python list
While using Python dictionary we may need to identify each element of the dictionary uniquely. For that we have to assign unique IDs to each of the element in the dictionary. In this article we will see how to assign the same unique Id to an element if it is repeated in a Python dictionary.With enumerate() and OrderedDict.fromkeys()The enumerate function expands a given dictionary by adding a counter to each element of the dictionary. Then we apply the OrderedDict.fromkeys() which will extract the same value of the counter from the dictionary hence eliminating the duplicates values of IDs.Example Live Demofrom collections ...
Read MoreSimple Chat Room using Python
In this article we will see how to make a server and client chat room system using Socket Programming with Python.The sockets are the endpoints of any communication channel. These are used to connect the server and client. Sockets are Bi-Directional. In this area, we will setup sockets for each end and setup the chatroom system among different clients through the server. The server side has some ports to connect with client sockets. When a client tries to connect with the same port, then the connection will be established for the chat room.There are basically two parts. The server side ...
Read MoreChanging Directions in Python
Suppose we have a list of numbers called nums, we have to find the number of times that the list changes from positive-to-negative or negative-to-positive slope.So, if the input is like [2, 4, 10, 18, 6, 11, 13], then the output will be 2, as it changes the direction at 10 (positive-to-negative), and then at 6 (negative-to-positive).To solve this, we will follow these steps −To solve this, we will follow these steps −for i in range 1 to size of nums - 1, doif nums[i-1] < nums[i] > nums[i+1] or nums[i-1] > nums[i] < nums[i+1], thencount := count + 1return ...
Read MoreCell fusion in Python
Suppose we have a list of numbers called cells; this list is representing sizes of different cells. Now, in each iteration, the two largest cells a and b interact according to these rules: So, If a = b, they both die. Otherwise, the two cells merge and their size becomes floor of ((a + b) / 3). We have to find the size of the last cell or return -1 if there's no cell is remaining.So, if the input is like [20, 40, 40, 30], then the output will be 16, in first iteration, 40 and 40 will die, then ...
Read MorecamelCase in Python
Suppose we have a list of words, we have to concatenate them in camel case format.So, if the input is like ["Hello", "World", "Python", "Programming"], then the output will be "helloWorldPythonProgramming"To solve this, we will follow these steps −s := blank stringfor each word in words −make first letter word uppercase and rest lowercaseconcatenate word with sret := s by converting first letter of s as lowercasereturn retLet us see the following implementation to get better understanding −Example Live Democlass Solution: def solve(self, words): s = "".join(word[0].upper() + word[1:].lower() for word in words) return ...
Read MoreCaesar Cipher in Python
Suppose we have a lowercase alphabet string s, and an offset number say k. We have to replace every letter in s with a letter k positions further along the alphabet. We have to keep in mind that when the letter overflows past a or z, it gets wrapped around the other side.So, if the input is like "hello", k = 3, then the output will be "khoor"To solve this, we will follow these steps −Define a function shift(). This will take ci := ASCII of (c) - ASCII of ('a')i := i + ki := i mod 26return character ...
Read MoreBuying Cars in Python
Suppose we have a list of prices of cars for sale, and we also have a budget k, we have to find the maximum number of cars we can buy.So, if the input is like [80, 20, 10, 30, 80], k = 85, then the output will be 3 as we can buy three cars with prices 20, 10, 40To solve this, we will follow these steps −count := 0sort the list pricesfor i in range 0 to size of prices, doif prices[i]
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