Suppose we want to make student data type with data hiding and encapsulation. Students must have first_name, last_name, age and class items, but these variables cannot be accessible directly. We shall have to define some functions like get_firstname() set_firstname(), get_age() set_age() etc to retrieve and update variable values, and a to_string() function to display students details in this format (age, first_name, last_name, class). From the console take four parameters as input and set them using setter methods that we have defined, and show each items using getter methods and finally using to_string() method.So, if the input is likepriyam kundu 16 ... Read More

Suppose we have provided the first name, last name, age and class of a student in different lines. We shall have to write a program using structs in C++ to read them all and show in this format (age, first_name, last_name, class). The age and class will be of type integer, and first_name and last_name are of time string.So, if the input is likepriyam kundu 16 10then the output will be (16, priyam, kundu, 10)To solve this, we will follow these steps −define a structure with first_name, last_name of type string and age, cl of type integerread each line and ... Read More

Suppose we have two strings s and t, we shall have to find output in three lines, the first line contains lengths of s and t separated by spaces, the second line is holding concatenation of s and t, and third line contains s and t separated by space but their first characters are swapped.So, if the input is like s = "hello", t = "programmer", then the output will be5 10 helloprogrammer pello hrogrammerTo solve this, we will follow these steps −display length of s then print one space and length of tdisplay s + ttemp := s[0]s[0] := ... Read More

Suppose we have a string where we have few integers which are separated by comma. We shall have to separate them out and display each integer in different line. To do this we shall use stringstream (under sstream library) in C++. This is one string based stream class present in C++. We can use extraction operator () to insert something and str() functions to set contents of underlying string device object.So, if the input is like s = "56, 9, 85, 256, 47", then the output will be56 9 85 256 47To solve this, we will follow these steps −Define ... Read More

Suppose we have an array with n different elements. We shall have to reverse the elements present in the array and display them. (Do not print them in reverse order, reverse elements in place).So, if the input is like n = 9 arr = [2, 5, 6, 4, 7, 8, 3, 6, 4], then the output will be [4, 6, 3, 8, 7, 4, 6, 5, 2]To solve this, we will follow these steps −for initialize i := 0, when i < quotient of n/2, update (increase i by 1), do:temp := arr[i]arr[i] := arr[n - i - 1]arr[n - ... Read More

Suppose we have two numbers a and b. We shall have to define a function that can calculate (a + b) and (a - b) both. But using a function in C++, we can return at most one value. To find more than one output, we can use output parameters into function arguments using pointers, and call that function using addresses of those variables. Here in this problem we shall update a with a+b and b with a-b. When we call the function we shall have to pass the address of these two variables.So, if the input is like a ... Read More

Suppose we have four integers a, b, c and d. We shall have to find the greatest number among them by making our own function. So we shall create one max() function that takes two numbers as input and finds the maximum, then using them we shall find maximum of all four numbers.So, if the input is like a = 75, b = 18, c = 25, d = 98, then the output will be 98.To solve this, we will follow these steps −define a function max(), this will take x and yreturn maximum of x and ytake four numbers ... Read More

Suppose we have two digits a and b. We shall have to convert each digit into words and print them one by one. Printing digits into words means for a digit 5, it should print "Five".So, if the input is like a = 2, b = 6, then the output will beTwo Three Four Five SixTo solve this, we will follow these steps −if d < 0 and d > 9, then:return ("Beyond range of 0 - 9")otherwise when d is same as 0, then:return ("Zero")otherwise when d is same as 1, then:return ("One")otherwise when d is same as 2, ... Read More

Suppose we have a digit d, we shall have to convert it into words. So if d = 9, our output should be "Nine". If we provide some d which is beyond the range of 0 and 9, it will return appropriate output.So, if the input is like d = 3, then the output will be "Three".To solve this, we will follow these steps −Define a function solve(), this will take d, if d < 0 and d > 9, then:return ("Beyond range of 0 - 9")otherwise when d is same as 0, then:return ("Zero")otherwise when d is same as ... Read More

Suppose we have two numbers a and b, a is integer and b is a float. We shall have to take them from standard input and display the sum.So, if the input is like a = 10 b = 56.23, then the output will be Sum: 66.23To solve this, we will follow these steps −To display output into the standard output device we can use extraction operator ()ExampleLet us see the following implementation to get better understanding −#include using namespace std; int main(){    int a;    float b;    cout a >> b;    cout