Found 10805 Articles for Python

If you want to get an inversion of only first 16 bits of a number, you can take a xor of that number with 65535(16 1s in binary). examplea = 3 # 11 in binary b = a ^ 65535 print(bin(b))OutputThis will give the output −0b1111111111111100

If you want to get an inversion of only first 16 bits of a number, you can take a xor of that number with 65535(16 1s in binary). Forgetting a 2s complement, just add one to the result. For example,Examplea = 3 # 11 in binary b = (a ^ 65535) + 1 print(bin(b))OutputThis will give the output:0b1111111111111101

No this cannot be done. It's part of the Python language itself. That's how the language parses the expressions and builds parse and syntax trees. From the documentation:When performing mathematical operations with mixed operators, it is important to note that Python determines which operations to perform first, based on a pre-determined precedence. This precedence follows a similar precedence to most programming languages.

You can do Python operator overloading with multiple operands just like you would do it for binary operators. For example, if you want to overload the + operator for a class, you'd do the following −Exampleclass Complex(object):    def __init__(self, real, imag):       self.real = real       self.imag = imag    def __add__(self, other):       real = self.real + other.real       imag = self.imag + other.imag       return Complex(real, imag)    def display(self):       print(str(self.real) + " + " + str(self.imag) + "i")       a = Complex(10, 5)       b = Complex(5, 10)       c = Complex(2, 2)       d = a + b + c       d.display()OutputThis will give the output −17 + 17i

The help method in the interpreter is very useful for such operations. It provides a rich set of special inputs that you can give to it to get information about the different aspects of the language. Forgetting operator lists, here are some of the commands you can use:All operators>>> help('SPECIALMETHODS')Basic operators>>> help('BASICMETHODS')Numeric operators>>> help('NUMBERMETHODS')Other than operators you can also get attribute methods, callable methods, etc using −>>> help('MAPPINGMETHODS') >>> help('ATTRIBUTEMETHODS') >>> help('SEQUENCEMETHODS1') >>> help('SEQUENCEMETHODS2') >>> help('CALLABLEMETHODS')

Python and most mainstream languages do not allow changing how operators look. If you're trying to replace something like a == b with a equals b, you can't do that. In Python the restriction is quite intentional — an expression such as a equals b would look ungrammatical to any reader familiar with Python.

In this article, we will explain the correct name of the * operator available in python. In Python, you'll encounter the symbols * and ** used frequently. Many Python programmers, especially those at the intermediate level, are confused by the asterisk (*) character in Python. The *args argument is called the "variable positional parameter" and **kwargs is the "variable keyword parameter". The * and ** arguments just unpack their respective data structures.Using Asterisk ( * ) Operator in Multiplication  Algorithm (Steps) Following are the Algorithm/steps to be followed to perform the desired task − Create two variables and ... Read More

The += operator is syntactic sugar for object.__iand__() function. From the python docs:These methods are called to implement the augmented arithmetic assignments (+=, -=, *=, @=, /=, //=, %=, **=, =, &=, ^=, |=). These methods should attempt to do the operation in-place (modifying self) and return the result (which could be, but does not have to be, self).ExampleSo when you do something like −a = 6 # 110 in binary b = 5 # 101 in binary a &= b # a changes to and of 110 and 101, ie, 100, ie, 4 print(a)OutputThis will give the output −15a ... Read More

The += operator is syntactic sugar for object.__iadd__() function. From the python docs:These methods are called to implement the augmented arithmetic assignments (+=, -=, *=, @=, /=, //=, %=, **=, =, &=, ^=, |=). These methods should attempt to do the operation in-place (modifying self) and return the result (which could be, but does not have to be, self).ExampleSo when you do something like −a = 5 b = 10 a += b print(a)OutputThis will give the output −15a is being modified in place here. You can read more about such operators on https://docs.python.org/3/reference/datamodel.html#object.__iadd__.The =+ operator is the same as ... Read More

You can do this by iterating over the dictionary and filtering out zero values first. Then take the sum of the filtered values. Finally, divide by the number of these filtered values. examplemy_dict = {"foo": 100, "bar": 0, "baz": 200} filtered_vals = [v for _, v in my_dict.items() if v != 0] average = sum(filtered_vals) / len(filtered_vals) print(average)OutputThis will give the output −150.0You can also use reduce but for a simple task such as this, it is an overkill. And it is also much less readable than using a list comprehension.