C++ Articles - Page 233 of 719

Every system works on operations mainly in two modes to safeguard hardware’s computation. The two modes are −User ModeKernel ModeUser Mode −The OS mode in which all the user applications and programs will run. Here, the user instructions are worked on and softwares like playing music is run.Kernel Mode −The OS mode in which the hardware loads and its computations are performed. Only privileged instructions are allowed to run in kernel mode. Some common privileged instructions are −Input-Output ManagementSwitching modes between user mode and kernel mode.Interrupt managementDual Mode in OS is the switching of modes between the two modes and switching of mode ... Read More

Suppose we have two coordinates (sx, sy), and (tx, ty), we have to check whether we can move from starting point to ending point or not. Here we can move consists of taking a point (x, y) and transforming it to either (x, x+y) or (x+y, y).So if the inputs are (1, 1) and (4, 5), then the answer will be true, this is because move (1, 1) to (2, 1), then (3, 1), then (4, 1), then (4, 5).To solve this, we will follow these steps −while tx > sx and ty > sy, do −if tx > ty, ... Read More

Suppose we are at position (0, 0) We have a string represents consecutive directions using four letters. We have to check whether we can return at (0, 0) position after considering all of the given directions. The symbols areE for eastW for westN for northS for south.So, if the input is like "EENWWS", then the output will be true, move east two units, then go north, then west two units then again south, so this is the starting position.To solve this, we will follow these steps −l := size of moves arrayif l is same as 0, then −return truelft ... Read More

Suppose, we are given a string that is made of only two letters a and b. We have to find out if the string is of the form anbn, or in other words it contains n number of a's followed by n number of b's. If true, we return 1 otherwise 0.So, if the input is like "aaaaaaaaaaaabbbbbbbbbbbb", then the output will be true.To solve this, we will follow these steps −length := length of input_stringfor initialize i := 0, when i < length, update (increase i by 1), do &minusif input_string[i] is not equal to 'a', then −Come out ... Read More

Suppose, we are given a string that contains only lowercase letters. Our task is to find if there exists a substring in the given string that is a palindrome and is of even length. If found, we return 1 otherwise 0.So, if the input is like "afternoon", then the output will be true.To solve this, we will follow these steps −for initialize x := 0, when x < length of string - 1, increase x by 1, do −if string[x] is same as string[x + 1], then:return truereturn falseExample (C++)Let us see the following implementation to get better understanding − Live ... Read More

Suppose, we are given two strings, str1 and str2. str2 is a substring of str1, and we can delete str2 from str1. It is possible, that the string str2 appears multiple times in str1. Our goal here is to find out if str1 becomes a null string if we keep removing str2 from str1 multiple times. If it is possible we return 1, otherwise 0.So, if the input is like str1 = "CCCPPPPPP", str2 = "CPP"; then the output will be true.To solve this, we will follow these steps −while size of str1 > 0, do −index := return the ... Read More

To get the links present on the website using PowerShell, we can first retrieve the data from the webpage using the Invoke-WebRequest cmdlet.$req = Invoke-WebRequest -uri "https://theautomationcode.com" $reqOutputTo retrieve only links we can use that property and there you will also find some sub-properties like InnerHTML, Innertext, href, etc as shown in the output.$req = Invoke-WebRequest -uri "https://theautomationcode.com" $req.LinksOutputinnerHTML : Scripts innerText : Scripts outerHTML : Scripts outerText : Scripts tagName : A href : https://theautomationcode.com/scripts/ We need only links so we will use the href property.$req.Links | Select -ExpandProperty hrefOutputhttps://theautomationcode.com/2020/11/ https://theautomationcode.com/author/chiragce17/ ... Read More

The diameter of a binary tree is the (left_height + right_height + 1) for each node. So in this method we will calculate (left_height + right_height + 1) for each node and update the result . The time complexity here stays O(n).Let us first define the struct that would represent a tree node that contains the data and its left and right node child. If this is the first node to be created then it’s a root node otherwise a child node.struct Node {    int data;    struct Node *leftChild, *rightChild; };Next we create our newNode(int data) function that ... Read More

A matrix is said to be diagonally dominant matrix if for every matrix row, the diagonal entry magnitude of the row is larger than or equal to the sum of the magnitudes of every other non-diagonal entry in that row.Let us first define a constant int variable N with value 3 which represents our matrix dimensions.const int N = 3;The isDDM(int mat[N][N], int n) is a Boolean function that takes a copy of our matrix and the size of our matrix. Inside we iterate the rows and columns of our matrix using nested for loop. We then find the sum ... Read More

To consider the nodes that are passing between lines of slope -1. The diagonal traversal of the binary tree will be to traverse and print all those nodes present between these lines.Let us first define the struct that would represent a tree node that contains the data and its left and right node child. If this is the first node to be created then it’s a root node otherwise a child node.struct Node {    int data;    struct Node *leftChild, *rightChild; };Next we create our createNode(int data) function that takes an int value and assign it to the data ... Read More