# Check if a string follows anbn pattern or not in C++

C++Server Side ProgrammingProgramming

Suppose, we are given a string that is made of only two letters a and b. We have to find out if the string is of the form anbn, or in other words it contains n number of a's followed by n number of b's. If true, we return 1 otherwise 0.

So, if the input is like "aaaaaaaaaaaabbbbbbbbbbbb", then the output will be true.

To solve this, we will follow these steps −

• length := length of input_string
• for initialize i := 0, when i < length, update (increase i by 1), do &minus
• if input_string[i] is not equal to 'a', then −
• Come out from the loop
• if i * 2 is not equal to length, then −
• return false
• for initialize j := i, when j < length, update (increase j by 1), do −
• if input_string[j] is not equal to 'b', then −
• return false
• return true

## Example (C++)

Let us see the following implementation to get better understanding −

Live Demo

#include <bits/stdc++.h>
using namespace std;
bool solve(string input_string) {
int length = input_string.length();
int i;
for (i = 0; i < length; i++)
if (input_string[i] != 'a')
break;
if (i * 2 != length)
return false;
for (int j = i; j < length; j++)
if (input_string[j] != 'b')
return false;
return true;
}
int main() {
string input_string = "aaaaaaaaaaaabbbbbbbbbbbb";
cout << solve(input_string)<< endl;
return 0;
}

## Input

"aaaaaaaaaaaabbbbbbbbbbbb"

## Output

1
Published on 18-Jan-2021 11:49:45