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Suppose we have an array A, here A[i] is indicating the price of a given stock on day i. We have to find the maximum profit. We can complete as many transactions as we like. (Transaction means to buy and sell stocks). But we have to keep in mind that we may not engage in multiple transactions at the same time. So we have to sell the stock before buying the new one.Suppose the array is like A = [7, 1, 5, 3, 6, 4], then the result will be 7. As we can see, if we buy on day ... Read More
Suppose we have an array A, here A[i] is indicating the price of a given stock on day i. We have to find the maximum profit. We can complete at most one transaction. (Transaction means to buy and sell stocks). But we have to keep in mind that we may not engage in multiple transactions at the same time. So we have to sell the stock before buying the new one.Suppose the array is like A = [7, 1, 5, 3, 6, 4], then the result will be 5. As we can see, if we buy on day 2 (index ... Read More
Suppose a decimal number can be converted to its Hexspeak representation by converting it to an uppercase hexadecimal string at first, after that replacing all occurrences of the digit 0 with the letter O, and the digit 1 with the letter I.This kind of representation is valid if and only if it consists only of the letters in the set {"A", "B", "C", "D", "E", "F", "I", "O"}.So we have a string num representing a decimal integer N, we have to find the Hexspeak representation of N if it is correct, otherwise return "ERROR". So if num = “257”, then ... Read More
Suppose we have one tree and a sum. We have to find one path such that if we follow that path, we will get the sum that will be matched with the given sum. Suppose the tree is like [0, -3, 9, -10, null, 5] and the sum is 14, then there is a path 0 → 9 → 5To solve this, we will follow these steps.If the root is null, then return Falseif left and right subtree are empty, then return true when sum – root.val = 0, otherwise falsereturn solve(root.left, sum – root.val) or solve(root.right, sum – root.val)Let ... Read More
Suppose we have a m x n matrix filled with non-negative integers, find a path from top left corner to bottom right corner which minimizes the sum of all numbers along its path. Movements can only be either down or right at any point in time. So for example, if the matrix is like below131151421The output will be 7, the path will be 1, 3, 1, 1, 1, this will minimize the sumLet us see the steps −a := number of rows, b := number of columnsi := a – 1, j := b - 1while j >= 0matrix[a, j] ... Read More
Suppose we have one sorted array A. We have to generate one height-balanced binary search. In this problem, a height-balanced binary tree is actually a binary tree in which the depth of the two subtrees of every node never differs by more than 1. Suppose the array is like [-10, -3, 0, 5, 9]. So one possible output will be like: [0, -3, 9, -10, null, 5]To solve this, we will follow these steps.If A is empty, then return Nullfind the mid element, and make it rootDivide the array into two sub-arrays, left part of the mid element, and right ... Read More
Suppose there are three integer arrays arr1, arr2 and arr3 and they are sorted in strictly increasing order, we have to return a sorted array of only the integers that appeared in all of these three arrays. So if arrays are [1, 2, 3, 4, 5], [1, 2, 5, 7, 9], and [1, 3, 4, 5, 8], so the output will be [1, 5]To solve this, we will follow these steps −define an array called rescreate three maps f1, f2 and f3for i in range 0 to length of arr1f1[arr1[i]] increase by 1for i in range 0 to length of ... Read More
Suppose a dieter consumes calories[i], this indicates the calories on the i-th day. If we have an integer k, for every consecutive sequence of k days that is (calories[i], calories[i+1], ..., calories[i+k-1] for all 0 upper, so increase one point, lower = length of C, then come out from the looptemp := temp + C[right]return pointsExampleLet us see the following implementation to get better understanding − Live Democlass Solution(object): def dietPlanPerformance(self, c, k, l, u): temp = 0 for i in range(k): temp += c[i] right ... Read More
Suppose we have one binary tree. We have to find the maximum depth of that tree. The maximum depth of a tree is the maximum number of nodes that are traversed to reach the leaf from the root using the longest path. Suppose the tree is like below. The depth will be 3 here.To solve this, we will follow these steps.Here we will use the recursive approach. The method is solve(root, depth = 0)if the root is empty, then return depthotherwise return max of solve(left, depth + 1) and solve(left, depth + 1)Let us see the following implementation to get ... Read More
Suppose, there is a special keyboard with all keys in a single row. So if we have a string of length 26 indicating the layout of the keyboard (indexed from 0 to 25), initially our finger is at index 0. To type a character, we have to move your finger to the index of the next character. The time taken to move your finger from index i to index j is denoted as |i - j|. So if we want to type a string. we have to define a function to calculate how much time it takes to type it ... Read More